Match url with regex but leave specific string from match

Question

I want to match the following URL

/root/folder/123

without the /root in front of it. I was trying around with this pattern ((?!root).)*$ which I found in this answer: https://stackoverflow.com/a/406408/237312

but it doesn't work either, because it still matches oot/folder/123. I thought about something like (?!(root)+.)*$ which matches nothing, so I'm looking for an answer here.

Do you want to match the URL but return everything without /root or do you want to match URLs like this if they do not start wit /root? — Martin Ender
– Martin Ender, Commented Nov 5, 2012 at 10:51
I want to match URLs starting with /rootin front, but I don't want to match it. Kev's asnwer is exactly what I was looking for. — sascha
– sascha, Commented Nov 5, 2012 at 10:55

kev · Accepted Answer · 2012-11-05 10:49:59Z

2

You can use lookbehind syntax: (?<=...)

For example:

(?<=/root).*$

It'll match /folder/123.

answered Nov 5, 2012 at 10:49

kev

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Jiman · Accepted Answer · 2012-11-05 10:52:05Z

1

You could do this:

\/root(.+)

The first group, i.e., $1 will be /folder/123

answered Nov 5, 2012 at 10:52

Jiman

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