Print within Recursion function Python3

Question

the point of my recursion function is to print integers in reverse order. def rDisp(s): n=str(s) if n == "": return n else: return rDisp(n[1:]) + n[0]

def main():
    number=(int(input("Enter a number :")))
    rDisp(num)

main()

If within the main function I implement print(reverseDisplay(number)), it works, however, for the purpose of this code, I want the reverseDisplay function to do the printing. How would I go about implementing the print function into that block of code.

Thanks!

You use the print() function. I really don't know what you are asking. — Lennart Regebro
– Lennart Regebro, Commented Nov 7, 2012 at 6:28
Within the function, reverseDisplay(s), where do I implement the print function. Attempting to return print(reversedDisplay(n[1:])+n[0]) has not worked, and instead returns an error. — pythonhack
– pythonhack, Commented Nov 7, 2012 at 6:35

Lennart Regebro · Accepted Answer · 2012-11-07 07:05:16Z

1

Untested code:

def reversePrint(s):
    if not s: 
        return
    print(s[-1])
    reversePrint(s[:-1])

def main():
    number=input("Enter a number :")
    reversePrint(number)

main()

answered Nov 7, 2012 at 7:05

Lennart Regebro

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1 Comment

pythonhack Over a year ago

Yeah thanks! That's basically it but I just messed around with it until I got all of the output on the same line

pythonhack · Accepted Answer · 2012-11-07 09:00:47Z

0

Just got it

def reverseDisplay(s):
    n=str(s)
    if n == "":
        return n
    else:
        reverseDisplay(n[1:])
        b=n[0]
        print(b,end='')

answered Nov 7, 2012 at 9:00

pythonhack

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