how to covert map values into string in Java

Question

i am able to print my Out-put in this format System.out.println(map.get("email"));//this is printing fine but i am unable to print same value after assigning it into a String variable. i tried: String email=(String) map.get("email"); System.out.println("Email--"+email);//But this is not printing
How can i convert map values into string? Please help me.

My full code:

String url = "https://www.googleapis.com/oauth2/v1/userinfo?alt=json&access_token="
              + authResponse.accessToken; 
            final StringBuffer r = new StringBuffer(); 
            final URL u = new URL(url);
            final URLConnection uc = u.openConnection();
            final int end = 1000;
            InputStreamReader isr = null;
            BufferedReader br = null; 
            isr = new InputStreamReader(uc.getInputStream());
            br = new BufferedReader(isr);
            final int chk = 0; 
            String pat = "\"(.*)\": \"(.*)\",";
            Pattern pattern = Pattern.compile(pat);
            Matcher matcher = null;
            Map map = new HashMap();

            while ((url = br.readLine()) != null)
            {
                if ((chk >= 0) && ((chk < end))) {
                    matcher = pattern.matcher(url);
                    if(matcher.find()) {
                        map.put(matcher.group(1), matcher.group(2));
                    }
                    //r.append(url).append('\n');
                }
            }
              System.out.println(map.get("email")); 
              String email=(String) map.get("email"); 
              System.out.println(email);

Rohit Jain · Accepted Answer · 2012-11-09 07:15:42Z

5

Always use Generic type when using any collection or Map, unless of course you are using Java version older than 1.5. So, declare your Map as : -

Map<String, String> map = new HashMap<String, String>();

And then you won't need a typecast at all. map.get("email") will give you String type result only.

edited Nov 9, 2012 at 7:15

answered Nov 9, 2012 at 6:38

Rohit Jain

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1 Comment

John Dvorak Over a year ago

+1 for suggesting the correct solution, not just fixing the code

Abubakkar · Accepted Answer · 2012-11-09 06:38:19Z

3

Try this:

String email=map.get("email").toString();

answered Nov 9, 2012 at 6:38

Abubakkar

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Comments

Kumar Vivek Mitra · Accepted Answer · 2012-11-09 06:54:11Z

1

Use toString() or "" with +,

String s = map.get("email").toString();

Or

String s = map.get("email")+"";

- And always prefer using Generics with Collection, so you enter specific type into the collection and get that specific type out of the collection.

Eg:

Map<String, String> map = new HashMap<String, String>();

edited Nov 9, 2012 at 6:54

answered Nov 9, 2012 at 6:38

Kumar Vivek Mitra

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2 Comments

Xavier Over a year ago

If you want it to work with nulls, then use ""+, or String.valueOf(map.get("email")) (it will give the string "null" in both cases)

Xavier Over a year ago

That's what I'm saying. Only map.get("email").toString() won't work with nulls

Community · Accepted Answer · 2017-05-23 12:16:03Z

0

http://java.dzone.com/articles/two-ways-convert-java-map. Have a look at this link.Also Converting map values to string array convert Map Values into String Array.

edited May 23, 2017 at 12:16

CommunityBot

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answered Nov 9, 2012 at 6:38

Raghunandan

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Comments

Subhrajyoti Majumder · Accepted Answer · 2012-11-09 06:39:49Z

0

It has been recommended to use type specific Map if you are working on java 1.5+. Your Map deceleration would be Map<String,String> map.

Map<String,String> map = new HashMap<>(); // Diamond operator available in java 7 
String email= map.get("email");


Map<String,String> map = new HashMap<String,String>(); // for java 5+ 
String email= map.get("email");

answered Nov 9, 2012 at 6:39

Subhrajyoti Majumder

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