How to declare class in namespace from string [duplicate]

Question

Possible Duplicate:
PHP namespace with Dynamic class name

How to declare class from string?

code

$name = 'the_class';
require_once $name.'.php';
$class = new \resource\$name();

Parse error: syntax error, unexpected '$name' (T_VARIABLE), expecting identifier (T_STRING)

@WesleyMurch: That's incorrect. See some of the answers below for how to do this properly. — FtDRbwLXw6
– FtDRbwLXw6, Commented Nov 10, 2012 at 20:11
@drrcknlsn: That's fantastic, although very ugly. I'm still amazed that chosen syntax for namespaces was backslash, which is pretty much universally an escape character. — No Results Found
– No Results Found, Commented Nov 10, 2012 at 20:12
@Wesley Murch, it was one of the only unused characters available for syntax. — Jason McCreary
– Jason McCreary, Commented Nov 10, 2012 at 20:15
@JasonMcCreary: ★resource★classname() would be much cooler. — No Results Found
– No Results Found, Commented Nov 10, 2012 at 20:16
It's too bad that other characters couldn't be used, and have the interpreter simply recognize the context in which it was used. For example why would $class = new Resource.Classname(); be an issue unless it was a shortcoming of the compiler? There's no ambiguity because the . could never work for concatenation in that context (right?). Just some thoughts - I'm sure there's a reason, it's really over my head, and I've gotten used to the backslash and almost like it now. — No Results Found
– No Results Found, Commented Nov 10, 2012 at 20:20

Jason McCreary · Accepted Answer · 2012-11-10 20:16:41Z

7

$classPath = '\\resource\\' . $name;
$class = new $classPath;

Note: I like to be explicit with literal backslashes.

answered Nov 10, 2012 at 20:10

Jason McCreary

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FtDRbwLXw6 · Accepted Answer · 2012-11-10 20:10:34Z

4

The namespace needs to be part of the string:

$name = 'the_class';
require_once $name . '.php';
$className = '\resource\\' . $name;
$class = new $className();

answered Nov 10, 2012 at 20:10

FtDRbwLXw6

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