PHP How get words from string and store them in a simple array

Question

Please I have this string :

$s = "Cannes (06150-06400), Limoges (87000-87100-87280), 06000, Paris";

I want to store only words in an array, so I tried this :

$villes = explode(',', preg_replace('#\(([0-9\-]*)\)#', '', $s));

But in result I get this array :

array(4) {
          [0]=>
             string(7) "Cannes "
          [1]=>
             string(9) " Limoges "
          [2]=>
             string(7) "  06000" // This shouldn't be displayed in the array
          [3]=>
             string(6) " Paris"
         }

Please how could I modify the regex to get it work as I wish. Thanks.

what about str_word_count($string, 1)?

ADTC
– ADTC

2016-11-29 09:46:19 +00:00
Commented Nov 29, 2016 at 9:46 — ADTC
– ADTC, Commented Nov 29, 2016 at 9:46

irrelephant · Accepted Answer · 2012-11-11 09:00:12Z

3

Try:

<?php
$s = "Cannes (06150-06400), Limoges (87000-87100-87280), 06000, Paris";
preg_match_all("/[a-zA-Z]+/", $s, $villes);
var_dump($villes[0]);
?>

For single word names. Var dump:

array(3) {
  [0]=>
  string(6) "Cannes"
  [1]=>
  string(7) "Limoges"
  [2]=>
  string(5) "Paris"
}

answered Nov 11, 2012 at 9:00

irrelephant

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Comments

air4x · Accepted Answer · 2012-11-11 09:11:33Z

1

Try

$arr = preg_split('/\s*\(?[\d\-\s]*\)?\s*,\s*/', $s, -1, PREG_SPLIT_NO_EMPTY);
var_dump($arr);

Output

array(3) {
  [0] =>
  string(6) "Cannes"
  [1] =>
  string(7) "Limoges"
  [2] =>
  string(5) "Paris"
}

answered Nov 11, 2012 at 9:11

air4x

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Comments

Nick Maroulis · Accepted Answer · 2012-11-11 08:58:26Z

0

preg_match( '/[a-zA-Z\-\']+/', $s, $words );
var_dump( $words[0] );

answered Nov 11, 2012 at 8:58

Nick Maroulis

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Comments

user1792423 · Accepted Answer · 2012-11-11 09:03:24Z

0

you can use array for result.

$arr=explode(' ' , $s);
print_r($arr);

answered Nov 11, 2012 at 9:03

user1792423

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