Sorting subset of string array in Java, ignoring case [duplicate]

Question

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How to properly sort upper and lowercase Strings in Array in Android?

I have to sort subset of CLI arguments alphabetically. So, to sort subset the following code is used:

// Ignore args[0], sort the rest
Arrays.sort(args, 1, args.length);

And to sort ignoring case, I have to use some sort of comparator object. To sort subset with comparator, there is the following method signature:

Arrays.sort(array, from, to, comp);

Can it be done without creating comparator object on separate line, and include it in the Arrays.sort() signature (i.e. neat and understandable enough)?

Faruk Sahin · Accepted Answer · 2012-11-11 20:59:57Z

3

You can use the built in comparator String.CASE_INSENSITIVE_ORDER:

Arrays.sort(args, 1, args.length, String.CASE_INSENSITIVE_ORDER);

edited Nov 11, 2012 at 20:59

answered Nov 11, 2012 at 20:44

Faruk Sahin

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Brian Agnew · Accepted Answer · 2012-11-11 20:42:51Z

2

You can define and initialise an anonymous class implementing Comparator e.g.

new Comparator<Whatever> {
   public int compare(Whatever w1, Whatever w2) {
      // implementation
   }
   // etc...
}

and do this inline i.e. within the Arrays.sort() method.

Arrays.sort(array, from, to, new Comparator<Whatever>{....});

The downside is readability if the comparator implementation is non-trivial, and, of course, you can't use that comparator elsewhere. However if the comparator is particularly small, it may aid readability since the implementation is clearly visible.

answered Nov 11, 2012 at 20:42

Brian Agnew

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1 Comment

theUg Over a year ago

Non-trivial indeed. :) However, nice to know the options available for more advanced stuff.

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