Using Comparison Operators for Hex Values

Question

I want to create a function that performs a certain task only when a hex value indicates an upper or lower case letter, i.e., when the hex code is between 20 and 7A. Is there a way to make a statement in python that is logically equivalent to:

if a >= 20 and a <= 7A: perform stuff

? Do I just throw a 0x in front of it and magic happens?

In fact, even if you do a >= 0x41 and a <= 0x7a (or, more readably, ord('A') <= a <= ord('Z'), it's still wrong, because there are 6 non-alphabetic characters in that range. Why not use chr(a).isalpha()`? — abarnert
– abarnert, Commented Nov 13, 2012 at 20:37

Joran Beasley · Accepted Answer · 2012-11-13 18:16:47Z

13

yes ... you just throw a 0x and it becomes numeric ....

or int("7A",16) == 0x7A

0x20 <= a <= 0x7A you can also chain comparison operators like this (which translates roughly to "is a between val1 and val2")

answered Nov 13, 2012 at 18:16

Joran Beasley

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1 Comment

abarnert Over a year ago

And, even better, you can do ord('A') <= a <= ord('z') instead of having to remember the ASCII values (which isn't just a trivial win, given that the OP got the ASCII value of 'A' wrong).

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