PHP Undefined variable in a closure

Question

The following snippet returns a bunch of input fields but I'm unable to set their values because $data is undefined (it being inside a closure).

$row = array_map(function($n) {
    $name = sprintf('point[%0d]', $n+1);
    $value = $data['measurements'][$n];
    return form_input($name, $value, "class='input-mini'");
}, range($i*6, $i*6+5));

I know global variables are not cool. What's the best way to get around this?

Use function($n) use ($data) {

air4x
– air4x

2012-11-14 16:04:49 +00:00
Commented Nov 14, 2012 at 16:04 — air4x
– air4x, Commented Nov 14, 2012 at 16:04

Pavel · Accepted Answer · 2019-11-01 15:41:15Z

26

Inheriting variables from the parent scope

$row = array_map(function($n) use ($data) {
    $name = sprintf('point[%0d]', $n+1);
    $value = $data['measurements'][$n];
    return form_input($name, $value, "class='input-mini'");
}, range($i*6, $i*6+5));

edited Nov 1, 2019 at 15:41

Pavel

3367 silver badges17 bronze badges

answered Nov 14, 2012 at 16:04

aykut

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