Convert unsigned char* array to std::string

Question

I'm using this code to convert the unsigned char* (points to an array of 256 values) to std::string:

int ClassA::Func(unsigned char *dataToSend, int sendLength)
{
    std::stringstream convertStream;
    std::string dataToSendStr = "";

    for(int i=0; i<=sendLength; i++) convertStream << dataToSend[i];    

    while(!convertStream.eof()) convertStream >> dataToSendStr;
    ...
}

but then I have dataToSendStr in this format:

dataToSendStr "" 
[0]           0x00 
[1]           0x00 
[2]           0x04 
[3]           0xC0

if I now use this value I only get "" and not the important values [0-3]!

-> need something like: dataToSendStr "000004C0"

Thx for your help!

As an aside, you don't have to use the for() ... construct to write the elements to a stream. You can use copy( dataToSend, dataToSend+sendLength, ostream_iterator<string>(convertStream) ); if you want to avoid hand-written loops. — John Dibling
– John Dibling, Commented Nov 15, 2012 at 14:21
When you say "need something like", did you actually mean "this is the exact string I want given this input"? — Rook
– Rook, Commented Nov 15, 2012 at 14:24

hmjd · Accepted Answer · 2012-11-15 14:19:28Z

6

Use the IO manipulator std::hex if you want (which is what I think based on the need something like part of the question) a hexadecimal representation of the characters in dataToSend:

std::ostringstream convertStream;
convertStream << std::hex << std::setfill('0');

for (int i = 0; i < sendLength; i++)
{
    convertStream << std::setw(2) << static_cast<short>(dataToSend[i]);
}

answered Nov 15, 2012 at 14:19

hmjd

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