Actionscript 3.0 calling PHP function

Question

I´m aware that with

loader = new URLLoader();
loader.data;

it´s possible to get the entire data/information from a php page.. But I don't want a php page for every bit of information I want from to 'stream'.

So my Question is: Is it possible to have multiple functions/methods in a php script, and only call the method I require?

such as:

<?php
   function getColour1()
      echo "blue";

   function getColour2()
      echo "red";
?>

If "yes", 2 lines of code that show how, or link to an example would be greatly appreciated.

cheers, M

lostPixels · Accepted Answer · 2012-11-15 14:37:12Z

2

You can pass an "action" variable to PHP, then use if/else statements in PHP tp respond to that action.

answered Nov 15, 2012 at 14:37

lostPixels

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Comments

divillysausages · Accepted Answer · 2012-11-15 16:10:34Z

2

Check out the AMFPHP project: http://www.silexlabs.org/amfphp/

It does what you're looking for

answered Nov 15, 2012 at 16:10

divillysausages

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1 Comment

Jake Over a year ago

whoa. I don't doubt it works.. but i'm only starting off with Php and just want to push a few variables around.

Geert · Accepted Answer · 2012-11-15 14:36:33Z

1

You could call the page like this:

http://www.site.com/script.php?action=getColour1

Then in your code:

<?php

switch($_GET["action"]) {

    case "getColour1":
        getColour1();
        break;
    case "getColour2":
        getColour2();
        break;
    default:
        echo "Unknown action";
        break;
}

?>

answered Nov 15, 2012 at 14:36

Geert

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Comments

moonwave99 · Accepted Answer · 2012-11-15 14:38:40Z

1

You want to hear about Front Controller Pattern.

Moreover, you need to route your request to different functions - I advise you to use this beautiful library, if you don't want to go with a full framework MVC stack.

answered Nov 15, 2012 at 14:38

moonwave99

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Comments

The_asMan · Accepted Answer · 2012-11-15 14:48:07Z

0

$functionName = $_GET["action"];
$functionName() or call_user_func($functionName)

answered Nov 15, 2012 at 14:48

The_asMan

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