declare an array of N pointers to functions returning pointers to functions returning pointers to characters

Question

Ugly interview question: How would you declare an array of N pointers to functions returning pointers to functions returning pointers to characters in c++? Show it with and without typedef.

Let's say the functions take no params.

Is mine correct with typedef?

typedef char* (*f1)();
typedef f1 (*f2)();

f2 a[N];

std::array<std::function<std::function<char*()>*()>*, N> :) — Qaz
– Qaz, Commented Nov 19, 2012 at 2:05

Reuben Morais · Accepted Answer · 2012-11-19 02:12:04Z

1

typedef char *(*(*foo[])())();

But I definitely agree with @Xploit here. Don't ever write this.

answered Nov 19, 2012 at 2:12

Reuben Morais

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Comments

Thomas Matthews · Accepted Answer · 2012-11-19 02:26:47Z

0

Function returning pointer to characters:

typedef char * (*fpc)(void);

Function returning pointer to function returning pointer to characters:

typedef fpc (*fpa)(void);

Array of function pointers to functions returning pointer to function return pointer to characters:

fpa my_array[N];

I'll leave the non-typedef version to the OP. There should be no reason to banish typedefs.

answered Nov 19, 2012 at 2:26

Thomas Matthews

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1 Comment

Karthik T Over a year ago

didnt you just repeat the question? he is just asking if he is right.

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