Remove image and use CSS instead for data from database using PHP

Question

I have the PHP code as below:

 <?php 
                for ($i = 1; $i <= 5; $i++) {
                $checked = ($value['2.Capacity'] == $i) ? ' <img src="img/tick.jpg" width="20px" />' : '';
                echo  '<td>'.$checked.$i.'</td>';
                }

I need:

I want to remove the <img src="img/tick.jpg" width="20px" /> to put CSS style Bold + underlined I do not know how to fix this.

Note:

For the $value['2.Capacity'] it's data from database, it integer value 1 2 3 4 5.

Anyone help me please,Thanks.

Akhilraj N S · Accepted Answer · 2012-11-19 05:19:31Z

1

<?php 

            for ($i = 1; $i <= 5; $i++) {
            $checked = ($value['2.Capacity'] == $i) ? ' text-decoration: underline; font-weight: bold;' : '';
            echo  "<td style=$checked>$i</td>";
            }

answered Nov 19, 2012 at 5:19

Akhilraj N S

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1 Comment

Pov Nu Over a year ago

Thanks it works well now but need to add single quote to style=$checked like style='$checked'.

Raymond Saga · Accepted Answer · 2012-11-19 05:41:10Z

0

Basically you need to understand first the Conditional Statement you're using. You can check out this link for the explanation: http://davidwalsh.name/php-ternary-examples

$checked = ($value['2.Capacity'] == $i) ? ' <img src="img/tick.jpg" width="20px" />' : '';

This code is something like this:

$checked = (conditional statement) ? return true : return false;

The anwer of Akhilraj N S and Barmar will satisfy your needs.

answered Nov 19, 2012 at 5:41

Raymond Saga

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Comments

Barmar · Accepted Answer · 2012-11-19 06:03:00Z

0

for ($i = 1; $i <= 5; $i++) {
  $style = ($value['2.Capacity'] == $i) ? 'text-decoration: underline; font-weight: bold;" : ''     ;                         
  echo "<td><span style='$style'>$i</span></td>";
}

edited Nov 19, 2012 at 6:03

answered Nov 19, 2012 at 5:02

Barmar

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1 Comment

Barmar Over a year ago

Fixed my answer to use <span>, not <style>.

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