Codeacademy JavaScript - Section 2-1

Question

I took an AP computer science course a few years ago, I learned Java from it. I'm trying this Codeacademy now and I'm puzzled by this one question, can anyone explain this to me? Here is the question:

You are a creature of habit. Every week you buy 5 oranges. But orange prices keep changing!

You want to declare a function that calculates the cost of buying 5 oranges.
You then want to calculate the cost of the 5 all together.
Write a function that does this called orangeCost().
It should take a parameter that is the cost of an orange, and multiply it by 5.
It should log the result of the multiplication to the console.
Call the function where oranges each cost 5 dollars.

Here's my code:

var getCost = orangeCost (costOfOrange) {
    console.log(costOfOrange * 5);
};
getCost(5);

I believe it follows the syntax showed in earlier problems, but I'm getting this output:

SyntaxError: missing  before statement
Oops, try again. 
It looks like your syntax isn't quite right. 
Feel free to peek back at earlier exercises if you need help!

Madara's Ghost · Accepted Answer · 2012-11-19 23:10:15Z

3

Function definition in JavaScript can take one of two major forms:

function funcName(param1, param2, ...) { }

Or

funcName = function(param1, param2, ...) { }

Your example doesn't follow either. You probably want:

orangeCost = function(costOfOrange) {

answered Nov 19, 2012 at 23:10

Madara's Ghost

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Comments

bitoiu · Accepted Answer · 2012-11-19 23:11:12Z

0

It looks as simple as you forgot the function keyword and there's no orangeCost after the =:

var getCost = function (costOfOrange) {
    console.log(costOfOrange * 5);
};
getCost(5);

Did this help much?

answered Nov 19, 2012 at 23:11

bitoiu

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Comments

fthiella · Accepted Answer · 2012-12-27 19:28:33Z

0

I have solved mine using the following code:

var orangeCost = function (price) {
    console.log(price * 5);
};
orangeCost(5);

I believe it was asking to verify that the orangeCost be the function name, that's why it refuses any other thing though there's other ways to do this. Hope this helps as I was also surprised by this question and spend sometime :)

edited Dec 27, 2012 at 19:28

fthiella

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answered Dec 27, 2012 at 19:09

Raz

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Comments

TLama · Accepted Answer · 2014-01-25 22:35:25Z

0

var orangeCost = function (price) {

    console.log(price * 5);
}

orangeCost(5);

edited Jan 25, 2014 at 22:35

TLama

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answered Jan 25, 2014 at 22:16

Zayn Ali

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Comments

yayapipi · Accepted Answer · 2014-07-05 10:45:37Z

0

var orangeCost = function(price){
    var val = price*5;
    console.log(val);
}
orangeCost(7)

here is my code you could refer it

answered Jul 5, 2014 at 10:45

yayapipi

1

Comments

RachitSharma · Accepted Answer · 2014-08-14 11:32:08Z

0

enter image description here

Check it out dude. What you have done is that you are using orangeCost in place of function keyword.

answered Aug 14, 2014 at 11:32

RachitSharma

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Hugo Patrick Pires · Accepted Answer · 2015-06-02 10:21:28Z

0

This is what you should have done:

var orangeCost = function(price) {
    console.log(price * 5);
}

orangeCost(5);

answered Jun 2, 2015 at 10:21

Hugo Patrick Pires

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Comments

LJNielsenDk · Accepted Answer · 2015-08-23 22:27:50Z

0

Follow the instruction below:

var  functionName = function(parameterName){
//function definition.what you want to do 
}

In your case the code may be like this:

var orangeCost = function(price)
{
    console.log(price*5);
}
orangeCost(5);

edited Aug 23, 2015 at 22:27

LJNielsenDk

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answered Aug 23, 2015 at 21:17

Reduan Rafi

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Comments

ROMANIA_engineer · Accepted Answer · 2016-02-03 19:50:00Z

0

easy. Just create the function and evaluate it when printing out

var orangeCost = function (cost){
    console.log(cost * 5)
}

orangeCost(5);

edited Feb 3, 2016 at 19:50

ROMANIA_engineer

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answered Feb 3, 2016 at 19:40

Mwongera808

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Comments

Matheus Castro · Accepted Answer · 2016-04-07 05:13:59Z

0

var orangeCost = function (price) {
    console.log (price * 5);
};

orangeCost(5);

You shoud call orangeCost value instead of "price" which is the function name. there it goes.

edited Apr 7, 2016 at 5:13

Matheus Castro

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answered May 27, 2014 at 11:58

aakriti

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1 Comment

AdrianHHH Over a year ago

This code may help but it would be much more useful if there was also an explanation of how this code answers the users question

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