PHP Sorting Inner, Inner Array

Question

Okay I have an array like this:

array {
    [0] => array {
               [0] => array {
                         ["Time"] => "01:00:00"
                      }
               [1] => array {
                         ["Time"] => "00:00:00"
                      }
    }
    [1] => array {
               [0] => array {
                         ["Time"] => "01:00:00"
                      }
               [1] => array {
                         ["Time"] => "00:00:00"
                      }
    }
}

Now what I want to do is sort the inner inner array (the one with the time values) by the time values. Just so that inner array is sorted by the time values. How would I do this?

I do have PHP 5.3 installed if that is helpful.

xelber · Accepted Answer · 2012-11-20 22:06:06Z

2

foreach ( $array as $key => &$part )
{
    usort( &$part, function( $a, $b ) {
        return strtotime($a['Time'])-strtotime($b['Time']) > 0;
    });
}

answered Nov 20, 2012 at 22:06

xelber

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1 Comment

Will39 Over a year ago

The & before $part is deprecated, therefore I can't choose it as the final answer, thanks for your help though!

lukedays · Accepted Answer · 2012-11-20 22:03:50Z

1

Try this:

$arr = array(array(array("Time" => "01:00:00"), array("Time" => "02:00:00"), array("Time" => "00:00:00")),
             array(array("Time" => "02:00:00"), array("Time" => "01:00:00"), array("Time" => "00:00:00")));

$c = count($arr);
for ($i = 0; $i < $c; $i++) {
    sort($arr[$i]);
}

var_dump($arr); // outputs desired array

answered Nov 20, 2012 at 22:03

lukedays

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Comments

Community · Accepted Answer · 2023-11-17 20:16:04Z

0

function custom_map( $array ) {
    usort( $array, function( $a, $b ) {
        return strtotime($a['Time'])-strtotime($b['Time']) > 0;
    });
    return $array;
}

$new_array = array_map( "custom_map", $array );

https://www.php.net/manual/en/function.usort.php

https://www.php.net/manual/en/function.array-map.php

edited Nov 17, 2023 at 20:16

CommunityBot

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answered Nov 20, 2012 at 21:53

C. E.

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7 Comments

Will39 Over a year ago

No that's sorting the outermost array. I just want to sort the arrays that contain the Time value. (The outer array order should be unaffected).

C. E. Over a year ago

Sorry, I realized that and worked on an update but you beat me to it. Take a look at this.

Will39 Over a year ago

Warning: strtotime() expects parameter 1 to be string, array given

C. E. Over a year ago

Yeah, as I updated the code I inadvertently removed ['Time'] at the end. Please try the updated code.

Will39 Over a year ago

Okay that now leaves the first set of arrays in but removes the ones which contain the value Time and replaces them with NULL.

|

mickmackusa · Accepted Answer · 2025-01-29 13:59:17Z

0

I don't think it gets any simpler to sort the second level -- iterate the first level and call sort() on each occurrence. Because your string are presumably hh:ii:ss, it is completely safe to compare them as simple strings (no need to strtotime()).

Code: (Demo)

$array = [
    [
        ['Time' => "01:00:00"],
        ['Time' => "00:00:00"]
    ],
    [
        ['Time' => "01:00:00"],
        ['Time' => "00:00:00"]
    ]
];

array_walk($array, fn(&$v) => sort($v));
var_export($array);

Output:

array (
  0 => 
  array (
    0 => 
    array (
      'Time' => '00:00:00',
    ),
    1 => 
    array (
      'Time' => '01:00:00',
    ),
  ),
  1 => 
  array (
    0 => 
    array (
      'Time' => '01:00:00',
    ),
    1 => 
    array (
      'Time' => '00:00:00',
    ),
  ),
)

edited Jan 29 at 13:59

answered Feb 10, 2020 at 19:56

mickmackusa♦

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