Trying to extract strings using regex - Python

Question

I am trying to extract a portion from a string in python 2.7 using a regular expression (re module).

The best I can get is

res = "{{PakBusPort_somename} 11942 pakbus-port 1}\r\n{{Somename} 5436 CR800-series 2}"
p = re.compile('PakBusPort_')
m = p.findall( res )

Which will give me "PakBusPort_". But I also need it to give me the "somename" portion.

Basically I need everything in between { and } that starts with "PakBusPort_". I have tried

p = re.compile('PakBusPort_.*}}')

But no results.

I am a bit of a noob with regular expressions so any help would be appreciated.

NPE · Accepted Answer · 2012-11-20 23:20:53Z

4

In [71]: p = re.compile(r'{PakBusPort_(.*?)}')

In [72]: p.findall(res)
Out[72]: ['somename']

If you also need to include PakBusPort_, move the opening parenthesis:

In [73]: p = re.compile(r'{(PakBusPort_.*?)}')

In [74]: p.findall(res)
Out[74]: ['PakBusPort_somename']

The question mark is needed to make the match non-greedy, meaning that it'll stop at the first } rather than matching everything till the last one.

answered Nov 20, 2012 at 23:20

NPE

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2 Comments

g0atm1lk Over a year ago

Champion. I needed it to include the "PakBusPort_" portion but changing it to p = re.compile(r'{(PakBusPort_.*?)}') Gave me the result I was after.

BoppreH Over a year ago

Welcome to Stack Overflow, and don't forget to mark good solutions as Accepted Answer. It helps visitors and rewards the answerer.

John Gaines Jr. · Accepted Answer · 2012-11-20 23:22:15Z

0

You were close, this should give you back a list of tuples matching your regex:

res = '{{PakBusPort_somename} 11942 pakbus-port 1}\r\n{{Somename} 5436 CR800-series 2}'
p = re.compile('{(PakBusPort)_([^}]*)}')
m = p.findall( res )
print m

[('PakBusPort', 'somename')]

answered Nov 20, 2012 at 23:22

John Gaines Jr.

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