I have a Rails application which displays nested form in json format.
In the JSON Response i am also displaying an id field which represent another table.
How to display name corresponding to that id what i am getting so that i can display both name and id in my json format.
My controller show method
def show
@maintemplate = Maintemplate.find(params[:id])
respond_with (@maintemplate) do |format|
format.json { render :json => @maintemplate }
end
end
Thanks in advance....
Try this:
render :json => @maintemplate.to_json(:include => { :user => { :only => :name } } )
This will replace the user_id key with a user key and a value with only the name attribute of user, like this:
{
"user_id": "12"
"user": { "name": "..." }
...
}
You can then access the username in the json response with ["user"]["name"]. You can also access the user id with ["user_id"].
For more see the documentation on as_json.
Update:
Using the info provided in the comments, I think this is what you actually want:
render :json => @maintemplate.to_json(:include => { :routine => { :include => :user, :user => { :only => :name } } } )
@maintempalte is a nested form output? It's the result of a find method call, so it should be a model instance.Maintemplate model has_many :routines, or has_one :routine, or does it belong_to :routine? It's not clear from what you wrote above. When you describe your models, you should describe the associations (have_many, have_one, belongs_to etc.) Saying a model has an "array" is not really correct, it is an association not an array.Add to as_json method with the additional method-attributes you desire to the class in which you are calling.
class MainTemplate
...
def name
User.find(self.user_id).name
end
def as_json(options = {})
options[:methods] = :name
super(options)
end
end
render :json => @maintemplate.to_json?["user"]["name"]is the name of the user withuser_id = 12. That user id will also be in the JSON. I've updated my example below to make this clear (but the code is the same).