Regex Fetch part of string as number

Question

I've a string something like

<dt>Source:</dt>
<dd>
    Emergence: Title; 2005, Vol. 9 Issue 30, p120-203, 12p
</dd>

Now I am a regex to fetch different values for it, i.e. : Volume, issue, date etc so, I fetch entire text using :

var attr = jQuery("dl dt:contains('Source:') ~ dd:eq(0)").text();

And use regex to fetch different values, such as :

To fetch start page I use, following regex:

var regex = new RegExp("p\\d+(?=[-\\s]{1})");

var regexValPS = attr.match(regex);

Return value : p120, expected : 120

Similarly, to fetch Volume info, I use following, regex:

var regexVol = new RegExp("Vol.\\s\\d+");
var regexValVol = attributeVal.match(regexVol);

I get : Vol. 9 , I want : 9

Similarly I am getting issue number with "Issue" text :

var regEx = new RegExp("Issue\\s\\d+");
var regExVal = attributeVal.match(regEx);

I Should get : 30 instead : Issue 30

The problem is I can't use another regex to get the desired value, can't strip/parseInt etc, and the pattern must be able to fetch information in a single regex.

Community · Accepted Answer · 2020-06-20 09:12:55Z

1

Use grouping (...) and read its match »

Demo:

var str = "Emergence: Title; 2005, Vol. 9 Issue 30, p120-203, 12p";
var re = /p(\d+)(?=[\-\s])/;
document.writeln(re.exec(str)[1]); // prints: 120
re = /Vol\.\s(\d+)/;
document.writeln(re.exec(str)[1]); // prints: 9

Test it here.

edited Jun 20, 2020 at 9:12

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answered Nov 30, 2012 at 14:12

Ωmega

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Comments

gion_13 · Accepted Answer · 2012-11-30 13:55:21Z

1

Toget the desired info using a single regex, you need to take advantage of regex grouping:

var regEx = new RegExp("Issue\\s(\\d+)");
var regExVal = attributeVal.match(regEx)[1];

If you cannot modify the regex, you can maybe parse the resulting number :

var number = "Issue 30".replace(/\D/g, '');

answered Nov 30, 2012 at 13:55

gion_13

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Comments

Michael Berkowski · Accepted Answer · 2012-11-30 14:16:43Z

1

If I understand you correctly, you do not want to do further parsing on the string values returned by the .match() calls, but can accept a different regular expression if it returns the necessary values in one statement.

Your regex needs a capture group () to retrieve the desired numbers, and place them in an array index [] (the first index [0] will hold the entire matched string, and subsequent indices hold the () captured substrings).

Instead of new RegExp() you can use the simpler /pattern/ regex literal in this case, and it is possible to extract the desired value in a single statement for all cases.

var yourString = '<dt>Source:</dt>\
<dd>\
    Emergence: Title; 2005, Vol. 9 Issue 30, p120-203, 12p\
</dd>';

// Match the page, captured in index [1]
yourString.match(/p(\d+)(?=[-\s]{1})/)[1];
// "120"

// Match the Vol captured in index [1]
yourString.match(/Vol\.\s(\d+)/)[1];
// "9"

// Match the issue captured in index [1]
yourString.match(/Issue\s(\d+)/)[1];
// "30"

Here it is on jsfiddle

edited Nov 30, 2012 at 14:16

answered Nov 30, 2012 at 13:59

Michael Berkowski

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1 Comment

Ravish Over a year ago

thanx, you understood me correctly, all I wanted was to be able to parse the values in single Regex. Well, I can't directly use Group capture, but, let me see how I can make use of it... Thnx every1 for resoponses

palaѕн · Accepted Answer · 2012-11-30 14:27:24Z

0

Try this:

var attr = jQuery("dt:contains('Source:') ~ dd:eq(0)").text();
console.log(attr);
console.log(attr.match(/p(\d+)(?=[-\s]{1})/)[1]);
console.log(attr.match(/Vol\.\s(\d+)/)[1]);
console.log(attr.match(/Issue\s(\d+)/)[1]);

For more details: JQUERY REGEX EXAMPLES TO USE WITH .MATCH().

answered Nov 30, 2012 at 14:27

palaѕн

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