Search a number in string formatted array in PHP?

Question

My array looks like this:

array( '0|500|0.50', '501|1000|0.75' );

I am trying to run a search to get the KEY which has the searched value.

I made this function to search:

function cu_array_search($str,$array){
    foreach($array as $key => $value) {
        if(strstr($str,$value)) {
            return true;
        } else {
            return false;
        }
    }
}

and using it like this when checking:

if (cu_array_search(500,$array) {

but it never return true, despite that 500 exists in first key in array .

How to resolve this?

Thanks

xdazz · Accepted Answer · 2012-12-01 11:54:00Z

2

strpos will make you function return true even that's 0.5001 but not 500.

You should explode the value by |, then check whether the number in the array.

function cu_array_search($num, $array){
  return count(array_filter($array, function ($var) use ($num) {
    return in_array($num, explode('|', $var));
  })) > 0;
}

answered Dec 1, 2012 at 11:54

xdazz

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Comments

user1726343 · Accepted Answer · 2012-12-01 11:50:39Z

1

The haystack is the first argument, not the second:

if(strstr($value,$str)) {

Additionally, strpos is faster at this, so you should use:

function cu_array_search($str,$array){
    foreach($array as $key => $value) {
        if(strpos($value,$str) !== false) {
            return $key;
        } else {
            return false;
        }
    }
}

answered Dec 1, 2012 at 11:50

user1726343

1 Comment

user1726343 Over a year ago

@AhmedFouad You should use xdazz's solution, there are cases where string searching might retrieve incorrect results for your scenario.

Muthu Kumaran · Accepted Answer · 2012-12-01 11:54:26Z

0

First, strstr parameters are wrong

Second, return false should be at the end of the loop.

Third, If you need KEY then You need to use return $key instead of return true

function cu_array_search($str,$array){
    foreach($array as $key => $value) {
        if(strstr($value, $str)) {
            return $key;
        }
    }
    return false;
}

edited Dec 1, 2012 at 11:54

answered Dec 1, 2012 at 11:48

Muthu Kumaran

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Comments

Abdullah Umer · Accepted Answer · 2012-12-01 13:31:10Z

0

This works fine

<?php

function cu_array_search($str, $array) {
    foreach($array as $key => $value) {
        $temp_array=explode('|', $value);
        if (in_array($str, $temp_array))
            return true;
    }
    return false;
}

$array = array( '0|500|0.50', '501|1000|0.75' );


if (cu_array_search(500, $array))
    echo "success";
else
    echo "failed" ;

?>

edited Dec 1, 2012 at 13:31

Abdullah Umer

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answered Dec 1, 2012 at 12:05

Shijin TR

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