Try this:
int value = Integer.parseInt("0101011", 2); // parse base 2
Then the bit pattern in value will correspond to the binary interpretation of the string "0101011". You can then write value out to a file as a byte (assuming the string is no more than 8 binary digits).
EDIT You could also use Byte.parseByte("0101011", 2);. However, byte values in Java are always signed. If you tried to parse an 8-bit value with the 8th bit set (like "10010110", which is 150 decimal), you would get a NumberFormatException because values above +127 do not fit in a byte. If you don't need to handle bit patterns greater than "01111111", then Byte.parseByte works just as well as Integer.parseInt.
Recall, though, that to write a byte to a file, you use OutputStream.write(int), which takes an int (not byte) value—even though it only writes one byte. Might as well go with an int value to start with.