Regex string parsing in Ruby

Question

I have this set (number of points variable, here 2):

A 
 This is some Text belonging to A
 This also belongs to A
B 
 This should be with B
 same with this
...
...

I want it to finally be a string like that:

A This is some Text belonging to A This also belongs to A
B This should be with B same with this

My try was something like:

answer.scan(/^([A-Z].+?(?=^[A-Z]))/m).map { |d| d.delete("\n") }.join("\n")

The problem is that this doesn't match the last set (you can assume the string ends with the last set) any ideas? :)

edit1: fixed a coyping error & tried a new regex in Rubular which kind of works but still has some unnecessary matches?

@ nikola. most questions didnt really get "good" or productive answers except maybe the Backbone one, which I abandoned since I stopped that project. Therefore I can't really say if its correct or not. (And the Question concerning tabs probably didn't belong here anyhow) — algorithms
– algorithms, Commented Dec 5, 2012 at 9:58

AJcodez · Accepted Answer · 2012-12-05 10:25:19Z

4

text = <<EOS
A 
 This is some Text belonging to A
 This also belongs to A
B 
 This should be with B
 same with this
 variable line
EOS

text.gsub(/\s?\n\s/, ' ')

# Outputs: 
# A This is some Text belonging to A This also belongs to A
# B This should be with B same with this variable line

answered Dec 5, 2012 at 10:25

AJcodez

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2 Comments

algorithms Over a year ago

think that would only work for 2 sets? with 3 it doesnt seem to insert a newline between 2 and 3

algorithms Over a year ago

with set I mean an upper case letter and then some text. have managed to do it now, although it seems a bit messy...

algorithms · Accepted Answer · 2012-12-05 10:50:17Z

1

answer = answer
.scan(/^([A-Z].+?(?=^[A-Z]))|(^[A-Z].+?\Z)/m)
.map {|item| item.reject { |i| i.nil? } }
.map { |d| d[0].delete("\n") }
.join("\n")

seems to work for now... probably not the best possible way though

answered Dec 5, 2012 at 10:50

algorithms

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