Getting multiple values of checkbox from a loop

Question

while($row = mysql_fetch_array($result)){       
echo '<tr>
        <td>'.$row[0].'</td>
        <td>'.$row[1].'</td>
        <td>'.$row[2].'</td>';
        $price=$row['price'];
        echo "<td><input type='checkbox' name='er' value='$price'></td>";
echo "</tr>";

PHP file

 <?php
       $ercharge=$_POST['er'];
       echo $ercharge;
?>

I have a list of charges that was from a mysql table and it has a checkbox for each item so it would compute the sum. The above code works and it outputs the price of the checked item. The problem is, it's only one item. When multiple items are checked, only one is outputted.

Is your all check box having same name?

Toretto
– Toretto

2012-12-05 14:04:11 +00:00
Commented Dec 5, 2012 at 14:04 — Toretto
– Toretto, Commented Dec 5, 2012 at 14:04
@Tornado well yes since they are in a loop.

user1551672
– user1551672

2012-12-05 14:07:14 +00:00
Commented Dec 5, 2012 at 14:07 — user1551672
– user1551672, Commented Dec 5, 2012 at 14:07
see my answer may solve your problem

Toretto
– Toretto

2012-12-05 14:13:12 +00:00
Commented Dec 5, 2012 at 14:13 — Toretto
– Toretto, Commented Dec 5, 2012 at 14:13

Kickstart · Accepted Answer · 2012-12-05 14:05:12Z

1

Try this:-

echo "<td><input type='checkbox' name='er[]' value='$price'></td>";

answered Dec 5, 2012 at 14:05

Kickstart

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3 Comments

Eoin Murphy Over a year ago

This should be the answer. But i think the OP is looking for the sum. Which he can use array_sum( $_POST['er'] ) to get the result

user1551672 Over a year ago

It has an error. It says. Array to string conversion That code is on a form so when it is submitted, it will then be computed.

Kickstart Over a year ago

Doing this means that the 'er' variable returned to the script is an array with one element for each entry. You need to loop through the elements of this array to process them (maybe adding them up, or whatever else you need to do with them)

Toretto · Accepted Answer · 2012-12-05 14:35:09Z

1

Try this it may help you

echo "<td><input type='checkbox' name='er[]' value='$price'></td>";
echo "</tr>";

$recharge=$_POST['er'];

foreach($recharge as $val)
{
     echo $val;
}

Or you can just do this without using foreach

$arra_val=array_sum($recharge);

you just need to put the value in to some variable and echo it.

edited Dec 5, 2012 at 14:35

answered Dec 5, 2012 at 14:12

Toretto

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4 Comments

user1551672 Over a year ago

Thank you! This totally works! Now all i have to do is add those values. How would I add those?

Toretto Over a year ago

where do you want to add those values?

Toretto Over a year ago

@user1551672 I have just modified my answer with another solution check if it works.

Toretto Over a year ago

@user1551672 You just need to insert this value to some variable and echo it.see my updated answer.

Michoel · Accepted Answer · 2012-12-05 14:06:41Z

0

If you want to pass a number of elements in an array append the name with square brackets, so it would be:

echo "<td><input type='checkbox' name='er[]' value='$price'></td>";

And the result of $_POST['er'] would be an array of all of the checkbox values.

answered Dec 5, 2012 at 14:06

Michoel

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Comments

Ja͢ck · Accepted Answer · 2012-12-05 14:38:35Z

0

The input box name should reflect that it's an array by adding the [] suffix:

echo '<td><input type="checkbox" name="er[]" value=" . htmlspecialchars($row['price']) . "></td>';

Then, to process the sum after making sure the input validates as proper values:

if ($ers = filter_input(INPUT_POST, 'er', FILTER_VALIDATE_FLOAT, FILTER_FORCE_ARRAY)) {
    $ercharge = array_sum($ers);
}

edited Dec 5, 2012 at 14:38

answered Dec 5, 2012 at 14:16

Ja͢ck

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1 Comment

Ja͢ck Over a year ago

@user1551672 Sorry, forgot to add a parameter to filter_input. Updated answer.

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