PHP call function with parameter using array

Question

function myFunc($x, $y) {
    echo "x : {$x}";
    echo "y : {$y}";
}
$params = array("y" => 1, "x" => 2);

Is it possible to call myFunc like using call_user_func_array function but the keys of array will automatically set the right parameter in the function? Is there any function to do this or is it possible to create this function? for example :

call_func('myFunc', $params);

and the result would be like this

x : 2
y : 1

Thanks.

You can get parameters are myFunc($param); and then use extract($param); — Riz
– Riz, Commented Dec 6, 2012 at 15:11
@KevinM1 of course, but the result is x -> 1 and y -> 2 for the case above. — Darwin Gautalius
– Darwin Gautalius, Commented Dec 6, 2012 at 15:13

Ry- · Accepted Answer · 2012-12-06 15:31:06Z

7

There might be a simpler way to do this, but reflection should work too:

function call_func_keys($functionName, $args) {
    $f = new ReflectionFunction($functionName);
    $inOrder = array();

    foreach($f->getParameters() as $param) {
        if(array_key_exists($param->name, $args)) {
            $inOrder[] = $args[$param->name];
        } else {
            $inOrder[] = $param->getDefaultValue(); # Will throw a reflection exception if not optional
        }
    }

    call_user_func_array($functionName, $inOrder);
}

Here's a demo.

edited Dec 6, 2012 at 15:31

answered Dec 6, 2012 at 15:11

Ry-♦

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8 Comments

SDC Over a year ago

+1 for a good solution that does the job. Not sure I'd use it myself in production though; Reflection always leaves me feeling a bit dirty. What would the performance be like on this?

Darwin Gautalius Over a year ago

wow, that works perfectly. thanks! But, i'm getting a warning Warning: array_key_exists(): The first argument should be either a string or an integer in C:\xampp\htdocs\index.php on line 7. How to remove it?

Ry- Over a year ago

@DarwinGautalius: Sorry, I had a previous version that accidentally used $param there; try it again.

pocesar Over a year ago

@SDC Reflection is good because it doesn't actually instantiate the class or load the real function, of course it will be a small performance hit, but it'll be negligible, you won't be doing it in a loop with million iterations (i hope), otherwise you wouldn't be using PHP ;)

Ry- Over a year ago

@DarwinGautalius: And, in case you're working with optional values, I just changed it so that it handles those better. If not, then ignore this :)

|

jaco · Accepted Answer · 2012-12-06 15:27:15Z

1

UPDATED!

Usually you should use call_user_func_array function.

And it should be used this way:

function myFunc($x, $y) {
   echo "x : {$x}";
   echo "y : {$y}";
}
$params = array("y" => 1, "x" => 2);

call_user_func_array('myFunc', $params);

But in your case, you definitely use Reflection. The @minitech answer is just great.

edited Dec 6, 2012 at 15:27

answered Dec 6, 2012 at 15:09

jaco

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3 Comments

Ry- Over a year ago

param_arr: The parameters to be passed to the callback, as an indexed array. So no, it doesn't work. codepad.viper-7.com/wQ7u8C

Darwin Gautalius Over a year ago

of course, but the result is x -> 1 and y -> 2 for the case above.

SDC Over a year ago

the whole point of the question is the he wants to do it in a way that call_user_func_array doesn't seem to support, and asking if there's a way to do it. Your answer doesn't give him anything beyond what he had already tried.

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