auto increment list index in python

Question

Watch index n ( and y)

n = 0
while(0 < y):
  result[ n += 1] = items[y -= 1]

So the above is accepted syntax. Is there an elegant way to do this, in the order of Java's

result[ n++] = items[--y]

@Lev Levitsky, if this helps: for an example of what I am trying to do see en.wikibooks.org/wiki/Algorithm_Implementation/Sorting/… . I am wondering about combining the two steps: array[i] = a and i += 1. I suppose it may not be such a big deal. Nonetheless that's the question. — kasavbere
– kasavbere, Commented Dec 6, 2012 at 19:06

Lev Levitsky · Accepted Answer · 2012-12-06 18:01:53Z

1

No, this is not accepted syntax.

If I understand correctly what you are trying to do, the pythonic way would be

result = items[::-1]

or

result = list(reversed(items))

(the reversed function itself returns an iterator, not a list).

answered Dec 6, 2012 at 18:01

Lev Levitsky

66.4k23 gold badges155 silver badges184 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

kasavbere Over a year ago

That's not what I am trying to do. The question is straight forward: auto incrementing the index n: result[ n += 1]. Thanks for your response, though.

Lev Levitsky Over a year ago

@kasavbere The point is, in Python you usually don't use indexes in operations like this. In this case you are even avoiding the need of an explicit loop. Using unjustified C-like or Java-like constructs in Python is commonly considered bad practice.

Collectives™ on Stack Overflow

auto increment list index in python

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related