I have one string like 010000200000, 000000200000, 020000200000. I want to create regex for this and want to check that first 2 digit will be only 01,00 & 02. And rest of the digit should be only from [0-6].
I don't want any space or any special character in this string. I try some of the regex available online but didn't help me exactly.
If anyone has any idea please kindly help.
This should parse them with your requirements.
java.util.regex.Pattern.matches("0[012][0-6]+", "010000200000");
The first character is always a 0, followed by 1 character that is a 0, 1 or 2, followed by at least 1 character in the 0-6 range.
Straightforward
"0[012][0-6]*"
Start with 0, next a 0, 1 or 2, and than any amount of digits between 0 and 6.
I recommend you have a look at this tutorial.
If the number of digits and number of segments of your string is fixed, you could use
(?:0[012][0-6]{10}, ){2}0[012][0-6]{10}
If they are not, simply
(?:0[012][0-6]*, )*0[012][0-6]*
If you actually meant the given example is three separate strings, then it's even easier:
0[012][0-6]{10}
or
0[012][0-6]*
All this uses is character classes and repetition.
Note that these will only behave as you like when you use them with Pattern.matches. If not, surround them with ^...$ to make sure there is nothing else in front of or after this pattern.
java.util.regex.Pattern.matches("0[0-2]{1}[3-6]{10}", "015453356543")
This is the what exactly needed regular expression...yes?
0-2 is also allowed for the 10 trailing digits. And the {1} is (always) redundant.What about 0[0-2][0-6][0-6][0-6][0-6][0-6][0-6][0-6][0-6][0-6][0-6]? Obviously I guessed you need a fixed length string of 12 chars, otherwise 0[0-2][0-6]+ would be ok.
0[0-2][0-6]{10}