PHP multidimensional array to html table

Question

I have an multidimensional array which I'm trying to output as a table, here is my array;

$marksarray=     
array(3) {
      [0]=>
      array(2) {
        [0]=>
        string(1) "8"
        [1]=>
        string(1) "0"
      }
      [1]=>
      array(2) {
        [0]=>
        string(1) "9"
        [1]=>
        string(1) "1"
      }
      [2]=>
      array(2) {
        [0]=>
        string(2) "13"
        [1]=>
        string(1) "2"
      }
    }

So far I have my code like this;

echo "<table><tr><td>Question</td><td>Rating</td></tr>";
     foreach ($marksarray as $mks){
         foreach ($mks as $qid=>$rate){
            echo "<tr><td>".$qid."</td><td>".$rate."</td></tr>";
          }
    }
echo "</table></div>";

But my output is; enter image description here

What is that i'm doing wrong?

I need to pimply output the qid against the rating; Such as, 8 =>0, 9=>1, 13=>2 — Udy Warnasuriya
– Udy Warnasuriya, Commented Dec 7, 2012 at 16:41

Dharman · Accepted Answer · 2022-10-21 18:30:06Z

7

You've got one too many foreach's going on there. Try this instead:

echo "<table><tr><td>Question</td><td>Rating</td></tr>";
     foreach ($marksarray as $mks){
        echo "<tr><td>".$mks[0]."</td><td>".$mks[1]."</td></tr>";
    }
echo "</table></div>";

For future reference, it makes your code far easier to understand if you use an array of associative arrays with meaningful keys. e.g.

$marksarray = array(
    array('qid' => 8, 'rating' => 0), 
    array('qid' => 9, 'rating' => 1), 
    array('qid' => 13, 'rating' => 2)
);

Then your loop would look like this:

foreach ($marksarray as $mark){
    echo "<tr><td>".$mark['qid']."</td><td>".$mark['rating']."</td></tr>";
}

Better still, you should use MVC (Model, View, Controller) and pass this data into a view...but that's another subject entirely.

edited Oct 21, 2022 at 18:30

Dharman♦

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answered Dec 7, 2012 at 16:41

RobMasters

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Comments

Luke · Accepted Answer · 2012-12-07 16:55:06Z

When you echo your array, you are outputting the key rather than the actual values. Hence why you're getting '0' and '1's in your first column.

If you are stuck with the array layout that you currently have, you want the following code:

echo "<table><tr><td>Question</td><td>Rating</td></tr>";
     foreach ($marksarray as $mks){
        echo "<tr><td>".$mks[0]."</td><td>".$mks[1]."</td></tr>";
     }
echo "</table></div>";

... so that you are making use of the key values to pull out the matching values that you want to show.

If you're not stuck with the array structure that you have now, you'd have to structure your array like so, to make use of the key and pair values:

$marksarray = array(
    "8" => 0,
    "9" => 1,
    "13" => 2,
);

and use the code:

echo "<table><tr><td>Question</td><td>Rating</td></tr>";
     foreach ($marksarray as $qid => $rate){

        echo "<tr><td>".$qid."</td><td>".$rate."</td></tr>";

     }
echo "</table></div>";

... this way you are making clear reference to your key and pair values within your code.

devanand · Accepted Answer · 2012-12-07 16:42:36Z

0

change the echo line to

   echo "<tr><td>".$rate[0]."</td><td>".$rate[1]."</td></tr>";

Is it working?

answered Dec 7, 2012 at 16:42

devanand

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Comments

jchapa · Accepted Answer · 2012-12-07 16:43:23Z

0

This is outputting correctly, and your loops look fine. What I think you mean to do in your array is something like:

$marksarray = array(
    "8" => "0",
    "9" => "1",
    "13" => "2"
);

Then change your loop to:

echo "<table><tr><td>Question</td><td>Rating</td></tr>";
         foreach ($marksarray as $qid=>$rate){
            echo "<tr><td>".$qid."</td><td>".$rate."</td></tr>";
          }
echo "</table></div>";

answered Dec 7, 2012 at 16:43

jchapa

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Comments

arecaps · Accepted Answer · 2013-11-27 23:15:40Z

0

I know this is a little old, but I believe this code will do exactly what you want with the existing array.

echo "<table><tr><td>Question</td><td>Rating</td></tr>";
 foreach ($marksarray as $mks){
     echo "<tr>";
     foreach ($mks as $qid=>$rate){
        echo "<td>".$rate."</td>";
      }
      echo "</tr>";
}

echo "</table></div>";

Is there any reason not to do it this way?

answered Nov 27, 2013 at 23:15

arecaps

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Comments

Hussain Jawadwala · Accepted Answer · 2015-06-26 23:22:26Z

0

try using this code

function printmarraytable($data){
                            echo "<table>";
                            foreach($data as $key=>$value){
                                echo "<tr><td>".$key."</td>";
                                if(is_array($value) || is_object($value)){
                                    echo "<td>".printmarraytable($value)."     </td>";
                                }else{
                                    echo "<td>".$value."</td></tr>";
                                }
                            }
                            echo "</table>";
                          }
                          printmarraytable($req);

answered Jun 26, 2015 at 23:22

Hussain Jawadwala

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