Create String array (in xml) from java array? (Android)

Question

ArrayAdapter<CharSequence> adapter = ArrayAdapter.createFromResource(RoutesActivity.this, directionArray, R.id.route_direction_spinner);

So, I'm trying to make a spinner, and I have a java String array (directionArray). My problem is Eclipse returns this error when hovering over "createFromResource": "The method createFromResource(Context, int, int) in the type ArrayAdapter is not applicable for the arguments (RoutesActivity, String[], int)" And gives me this Quick Fix: "Change type of 'directionArray' to 'int'." Basically, I have an array in Java that I need to use in an ArrayAdapter, but apparently it won't let me. Is there a way to create an xml resource from within java, and/or a way to bypass the above error?

AndroidPenguin · Accepted Answer · 2012-12-08 01:21:07Z

2

ArrayAdapter<String> adapter = new ArrayAdapter<String>(RoutesActivity.this, android.R.layout.simple_spinner_item, directionArray);

Use this then your standard:

Spinner spinner1 = (Spinner) findViewById(R.id.route_direction_spinner);
spinner1.setAdapter(adapter);

answered Dec 8, 2012 at 1:21

AndroidPenguin

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4 Comments

nicocolton Over a year ago

Tried what you said, didn't work, but it gave me the suggestion to change it to this: ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, android.R.layout.simple_spinner_item, directionArray); Seems to be working.

AndroidPenguin Over a year ago

Ah, basically you weren't using a CharSequence but a String. I should've caught that, my bad. Still I'm glad I helped :)

nicocolton Over a year ago

Haha, learning experience for me though. I'd upvote but I cant yet :P

AndroidPenguin Over a year ago

We were all there. In my case just started learning a few months ago from scratch. If it helps this is the tutorials I used to learn: youtube.com/course?list=EC2F07DBCDCC01493A - this guy is awesome.

Alex Lockwood · Accepted Answer · 2012-12-08 01:02:34Z

0

No, XML resources are parsed into binary format at compile time. You cannot create new XML resources at runtime.

answered Dec 8, 2012 at 1:02

Alex Lockwood

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