preg_replace regex if else

Question

Let's assume I use the following php function:

 preg_replace($search, $replace, $str);

I'm only able to modify the search and replace var. Is it possible to do the following replace:

test -> test test2

And

test 3 -> test3

I tried the following:

$search = '/test (?=*)/';
$replace = 'test($1)';

This works for the second case. But now I want to use a if, in order to say "if $1 is empty, add test2. But I'm only able to modify the search and replace var without using addition php. Is this even possible in regex?

$replace = 'test(${1})';

Xingjia Luo
– Xingjia Luo

2012-12-11 08:56:39 +00:00
Commented Dec 11, 2012 at 8:56 — Xingjia Luo
– Xingjia Luo, Commented Dec 11, 2012 at 8:56
Is there a space after the first "test"?

user1726343
– user1726343

2012-12-11 08:59:31 +00:00
Commented Dec 11, 2012 at 8:59 — user1726343
– user1726343, Commented Dec 11, 2012 at 8:59

Gareth Cornish · Accepted Answer · 2012-12-11 09:00:34Z

3

You can pass the search and replace parameters as arrays. So pass an array of search queries into the search parameter, and an array of corresponding replace strings in the replace parameter...

so, you might try:

$search = array('/test(\s?)$/','/test (?=*)/');
$replace = array('test test2','test($1)');
preg_replace($search, $replace, $str);

answered Dec 11, 2012 at 9:00

Gareth Cornish

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Comments

newman · Accepted Answer · 2012-12-11 09:02:40Z

0

I think for you task you should't use regexp. For this case you can use str_replace and two arrays - for search and for change

$str = str_replace(array("test", "test 3"), array("test test2", "test3"), $str);

answered Dec 11, 2012 at 9:02

newman

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1 Comment

webaware Over a year ago

Won't the first element ("test") prevent the second element from working? Not to spec!

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