Print numbers with spaces in Python3

Question

I have a list of numbers that I want to print as follows:

Currently I achieve this by the following ugly code:

for count in counts:
    s = str(count)[::-1]
    s = ' '.join([s[i:i+3][::-1] for i in range(0,len(s),3)][::-1])
    print('{:>11}'.format(s))

Is there anyway that format can achieve this immediately? I couldn't find anything in the documentation.

It doesn't matter how ugly code is when you can hide it in a well-documented function :-) — paxdiablo
– paxdiablo, Commented Dec 11, 2012 at 9:25
That is true, of course. But one of the credos of Python is simplicity, and that doesn't look simple at all. ;-) — nvcleemp
– nvcleemp, Commented Dec 11, 2012 at 15:32

poke · Accepted Answer · 2012-12-11 09:41:26Z

1

You could use the thousand-separator in the string formatter and replace that to your likings like this:

>>> nums = (1, 3, 11, 58, 451, 4461, 49957, 598102, 7437910, 94944685)
>>> for num in nums:
        print('{:>11,}'.format(num).replace(',', ' '))

          1
          3
         11
         58
        451
      4 461
     49 957
    598 102
  7 437 910
 94 944 685

answered Dec 11, 2012 at 9:41

poke

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