I have some text like:
DESC:manner How did serfdom develop in and then leave Russia ? ENTY:cremat What films featured the character Popeye Doyle ? DESC:manner How can I find a list of celebrities ' real names ?
I read them line by line and I want to convert each line to a string Array word by word .
like this:
Array = [DESC, :, manner, How, did, serfdom ,develop, in ,and ,then ,leave, Russia ,?]
String[] arr = str.replaceAll(":"," : ").split(" ");
The problem is that you want to keep some delimiters and not others (keep : and loose the spaces). I think you need a regular expresion to accomplish this. Something like this should do it:
String str = "DESC:manner How did serfdom develop in and then leave Russia ?";
String arr[] = str.split("((?<=:)|(?=:))|( )");
This uses the Lookahead and Lookbehind RegEx to find/keep the delimiter : while we added in a normal split for the space ( ) to trash those.
After this arr should be:
arr = [DESC, :, manner, How, did, serfdom, develop, in, and, then, leave, Russia, ?]
String value = ""; String[] values = value.split(" ");
This should get you the array by space as a delimiter.
For a more comprehensive solution, you can use boundary matchers, as described here
String s = "DESC:manner How did serfdom develop in and then leave Russia ?";
String[] split = s.split("\\b");
the split array contains what you are looking for.
u mean u want to split your string line to a string array.
there are two convenient ways to do this.
first of course is the split method. U can refer this method in the j2se String class.
second would be the regex pattern. U can refer the information in the j2se regex class either
For your example:
String[] part = line.split(":| ");
Where line would be one your example lines.
Note that there is a space after the | in the regex.
I would advise reading up on Regular Expressions and getting hold of a tool like Expresso to try them out.
Expresso: http://www.ultrapico.com/Expresso.htm
: instead of adding it as an element in the result.If you don't mind punctuation being removed from the result, String#split("\\W") (split on nonword characters) will do it:
// you've got this from the input parser
String inputLine = "DESC:manner How did serfdom develop in and then leave Russia ?";
String[] wordArray = inputLine.split("\\W");
That gives:
wordArray = [DESC, manner, How, did, serfdom, develop, in, and, then, leave, Russia]
If you need punctuation, I don't think a regex will be able to do it, since it does the split by destroying the matched character.
I don't think a regex will be able to do it - sure it can, you just need the corerct regex :)You can use Guava's Splitter:
Iterable<String> wordsIterable = Splitter.on(Pattern.compile("\\b")).trimResults().omitEmptyStrings().split(string);
String[] words = Iterables.toArray(wordsIterable, String.class);
String#split(" ")?