How to combine strings inside foreach into single string PHP

Question

I have code like this

$word = 'foo';
$char_buff = str_split($word);

foreach ($char_buff as $chars){
    echo var_dump($chars);
}

The output was

string(1) "f" 
string(1) "o" 
string(1) "o"

For some reasons, I want to make the output become only 1 string like this:

string(3) "foo"

I tried with this

$char.=$chars;
echo var_dump($char);

But it shows error Undefined variable: char.

If you want it all together, why are you splitting it?

Sampson
– Sampson

2012-12-13 14:37:48 +00:00
Commented Dec 13, 2012 at 14:37 — Sampson
– Sampson, Commented Dec 13, 2012 at 14:37
Define $char as an empty string before your loop

Mark Baker
– Mark Baker

2012-12-13 14:38:21 +00:00
Commented Dec 13, 2012 at 14:38 — Mark Baker
– Mark Baker, Commented Dec 13, 2012 at 14:38

Sampson · Accepted Answer · 2012-12-13 14:40:31Z

17

I'm going to assume that you have a good reason for splitting it up, only to put it back together again:

$word = 'foo';
$result = "";
$char_buff = str_split($word);

foreach ($char_buff as $char){
    $result .= $char;
}

echo var_dump($result);

Which outputs the following:

string(3) "foo"

answered Dec 13, 2012 at 14:40

Sampson

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1 Comment

Wakanina Over a year ago

All of you guys have a great answer but I choose Jonathan Sampson as the best answer. My purpose with this is I want to create a key based on the user inputted character. So first I convert each string characters to a variable, like $f, $o, and $o. Then each those variables have a unique string. And then I combine those unique strings, and store in my database. So basically the output will not "foo" again. That's why I need it.

SeanWM · Accepted Answer · 2012-12-13 14:40:51Z

2

str_split() converts a string to an array. There's no need to use this function if you want to keep the whole word.

answered Dec 13, 2012 at 14:40

SeanWM

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1 Comment

Wakanina Over a year ago

My purpose with this is I want to create a key based on the user inputted character. So first I convert each string characters to a variable, like $f, $o, and $o. Then each those variables have a unique string. And then I combine those unique strings, and store in my database. So basically the output will not "foo" again. That's why I need it. I just want to know the basic method to do this.

Rosme · Accepted Answer · 2012-12-13 14:47:13Z

2

I would just use implode, much like this: $string = implode('', $char_buff);

answered Dec 13, 2012 at 14:47

Rosme

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3 Comments

mickmackusa Over a year ago

Empty glue is the default setting, you can omit the empty string parameter in this case.

Rosme Over a year ago

@mickmackusa Back in 2012 when I wrote the answer, that was not the case...

mickmackusa Over a year ago

There is nothing in the changlelog to suggest that that is true. php.net/manual/en/function.implode.php Please site proof of your claim.

vectorialpx · Accepted Answer · 2012-12-13 14:40:59Z

1

So, why do you split it just to make it a string again?

$word='foo'
$char_buff = str_split($word);

$final = array();
foreach ($char_buff as $chars){
    $final[] = $chars;
}

var_dump( implode('', $final) );

answered Dec 13, 2012 at 14:40

vectorialpx

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1 Comment

mickmackusa Over a year ago

Empty glue is the default setting, you can omit the empty string parameter in this case.

user625529 · Accepted Answer · 2012-12-13 14:40:39Z

0

Sounds like you are looking for implode() http://php.net/manual/en/function.implode.php

As for the code you posted $chars .= $char; is probably what you were trying to do

answered Dec 13, 2012 at 14:40

user625529

Comments

Bart Friederichs · Accepted Answer · 2012-12-13 14:41:36Z

0

Kind of strange to split a string, and then glue it together again, but here goes:

$word='foo'
$char_buff = str_split($word);

// this is what is missing, you have to define a variable first
$newword = "";

foreach ($char_buff as $chars){
     $newword .= $chars;
}

echo var_dump($newword);

answered Dec 13, 2012 at 14:41

Bart Friederichs

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Comments

Tahir Yasin · Accepted Answer · 2012-12-13 14:48:40Z

0

<?php
$word = 'foo';
$char_buff = str_split($word);

// here is the trick
$length = count($char_buff);
$char_buff[$length] = $word;

foreach ($char_buff as $chars)
{
    echo var_dump($chars);
}
?>

answered Dec 13, 2012 at 14:48

Tahir Yasin

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Comments

xreyc · Accepted Answer · 2017-11-18 05:15:21Z

0

Maybe some of you are looking for this answer. I think var_dump() is no longer necessary for this problem.

<?php 
    if(isset($_POST['test'])){
        $result = '';
        for($x=1;$x<=4;$x++){
            $ans = $_POST['ans'.$x];
            $result .= $ans;
        } 
    echo $result; 
    }
?>

Here is the HTML

<form role="form" method="post" action="<?php echo $url;?>">
	<input type="checkbox" name="ans1" value="A">A 
	<input type="checkbox" name="ans2" value="B">B 
	<input type="checkbox" name="ans3" value="C">C 
	<input type="checkbox" name="ans4" value="D">D 
	<input type="submit" name="test" value="Submit Answer">
</form>

edited Nov 18, 2017 at 5:15

answered Nov 18, 2017 at 4:59

xreyc

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