Get PHP class namespace dynamically

Question

How can I retrieve a class namespace automatically?

The magic var __NAMESPACE__ is unreliable since in subclasses it's not correctly defined.

Example:

class Foo\bar\A -> __NAMESPACE__ === Foo\bar

class Ping\pong\B extends Foo\bar\A -> __NAMESPACE__ === Foo\bar (it should be Ping\pong)

ps: I noticed the same wrong behavior using __CLASS__, but I solved using get_called_class()... is there something like get_called_class_namespace()? How can I implement such function?

UPDATE:
I think the solution is in my own question, since I realized get_called_class() returns the fully qualified class name and thus I can extract the namespace from it :D ...Anyway if there is a more effective approach let me know ;)

Your solution is what I've had to do in personal code. codepad.viper-7.com/EgObtf — The Pixel Developer
– The Pixel Developer, Commented Dec 18, 2012 at 12:05
What you describe is not wrong behavior. See what those constants carry: php.net/language.constants.predefined - and as you've found a solution to your problem, you can answer your own question. — hakre
– hakre, Commented Dec 18, 2012 at 12:16
Check this one out. I think this is what you mean: stackoverflow.com/questions/2317343/… — Chris
– Chris, Commented Nov 25, 2013 at 13:01
I think this is what your're after: stackoverflow.com/questions/2317343/… — Chris
– Chris, Commented Nov 25, 2013 at 13:02

shadyyx · Accepted Answer · 2014-09-04 07:45:30Z

21

The namespace of class Foo\Bar\A is Foo\Bar, so the __NAMESPACE__ is working very well. What you are looking for is probably namespaced classname that you could easily get by joining echo __NAMESPACE__ . '\\' . __CLASS__;.

Consider next example:

namespace Foo\Bar\FooBar;

use Ping\Pong\HongKong;

class A extends HongKong\B {

    function __construct() {
        echo __NAMESPACE__;
    }
}

new A;

Will print out Foo\Bar\FooBar which is very correct...

And even if you then do

namespace Ping\Pong\HongKong;

use Foo\Bar\FooBar;

class B extends FooBar\A {

    function __construct() {
        new A;
    }
}

it will echo Foo\Bar\FooBar, which again is very correct...

EDIT: If you need to get the namespace of the nested class within the main that is nesting it, simply use:

namespace Ping\Pong\HongKong;

use Foo\Bar\FooBar;

class B extends FooBar\A {

    function __construct() {
        $a = new A;
        echo $a_ns = substr(get_class($a), 0, strrpos(get_class($a), '\\'));
    }
}

edited Sep 4, 2014 at 7:45

answered Dec 18, 2012 at 12:04

shadyyx

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5 Comments

The Pixel Developer Over a year ago

They're using __NAMESPACE__ in the parent class, but they want the namespace of the child class.

shadyyx Over a year ago

@MaximilianRuta Well, thank You for Your edit, but please, in the future only correct what is necessary to be corrected. All occurrences of You changed to you? This is my style of writing and to show some politeness so if You do not mind, let me keep my style of expressing myself. Thanks! Also thank to reviewers for approving such minor and not so much correct edit request... Well done!

Maximilian Ruta Over a year ago

The problem is that i have to change at least n chars for an edit request. Thats the reason why i had to change something else in your post.

Nick Manning Over a year ago

Why do You write like this?

apotek Oct 19 at 4:59

Why do I write like this?

David Lin · Accepted Answer · 2015-04-30 13:00:53Z

14

In PHP 5.5, ::class is available which makes things 10X easier. E.g. A::class

answered Apr 30, 2015 at 13:00

David Lin

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2 Comments

Jekis Over a year ago

Example php.net/manual/en/language.oop5.constants.php#example-179

Daniel-KM Over a year ago

or get_class() for dynamic classes.

Stephen Stephenson · Accepted Answer · 2021-05-25 23:35:48Z

11

Use Reflection class.

$class_name = get_class($this);

$reflection_class = new \ReflectionClass($class_name);

$namespace = $reflection_class->getNamespaceName();

answered May 25, 2021 at 23:35

Stephen Stephenson

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