PHP regular expression and URL parsing

Question

How can I utilize preg_replace in PHP to parse a url.

Say I have the url

and I want to access each part of the url such that

echo $protocol;

would print

http

or

echo $domain;

would print

google

and

echo $upperDomain;

prints

com

and finally,

echo $rest;

would print

?id=123

@Dagon That would make a perfect answer rather than a comment :) — Oldskool
– Oldskool, Commented Dec 18, 2012 at 23:47

cmbuckley · Accepted Answer · 2012-12-18 23:54:37Z

4

there is a function for that: parse_url()

$url = 'http://google.com?id=123';    
print_r(parse_url($url));

prints:

Array
(
    [scheme] => http
    [host] => google.com
    [query] => id=123
)

edited Dec 18, 2012 at 23:54

cmbuckley

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answered Dec 18, 2012 at 23:47

user557846

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1 Comment

cmbuckley Over a year ago

See also parse_str if you want to parse the query string too. Additionally, if you're interested in separating the TLD and the secondary domain, you might want to look at this question.

Pedro del Sol · Accepted Answer · 2012-12-18 23:47:32Z

0

parse_url() from the docs...

 mixed parse_url ( string $url [, int $component = -1 ] )

This function parses a URL and returns an associative array containing any of the   
various components of the URL that are present.

This function is not meant to validate the given URL, it only breaks it up into the 
above listed parts. Partial URLs are also accepted, parse_url() tries its best to   
parse them correctly.

answered Dec 18, 2012 at 23:47

Pedro del Sol

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