Java Regular Expressions with String replace

Question

I Need help with Java Regular Expressions?

I have a String "TA520" and "TA011" and I want to get the number without the leading digit using regular expressions. So I need the "520" and the "11" without the leading 0 digits. I have the expression aString = aString.replace("TA0* , ""); but this doesn't work. How would I do this with regular expressions in Java? Thank you.

"Doesn't work" is not a problem description.

melpomene
– melpomene

2012-12-20 01:00:36 +00:00
Commented Dec 20, 2012 at 1:00 — melpomene
– melpomene, Commented Dec 20, 2012 at 1:00

Reimeus · Accepted Answer · 2012-12-20 01:21:08Z

4

The problem here is that String.replace does not use regular expressions.

You need to use String.replaceAll.

aString.replaceAll("^TA0*", "")

or alternatively, using replaceFirst:

aString.replaceFirst("^TA0*", "")

This strips away the leading "TA" plus any optional leading zeros.

edited Dec 20, 2012 at 1:21

answered Dec 20, 2012 at 0:56

Reimeus

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