Javascript: Passing arguments from multiple functions to 1 function

Question

I have several functions that evaluate some variables and come up with a result

For example:

function first(){
   //variable declarations
   var result1 = a+b
}

function two(){
   //variable declarations
   var result2 =c+d 
}

I want to pass both of those results to another function

function three( result1, result2 ) {
   var finalResult = result1 + result2;
}

My question is where do I call function 3 from. because in reality I have about 10 functions with results I need to pass. Do I put three(result#) at the end of each???

thankyou

Where are a, b, c, and d coming from? Are they global variables? — Lukas
– Lukas, Commented Dec 20, 2012 at 1:57
just to elaborate each function takes a value from the form field and then uses switch case to assign a score. It is the scores that I then want to pass to the main function to add up. — Wenz
– Wenz, Commented Dec 20, 2012 at 1:59
Where do I call 3 from. How can we answer that? Call it from wherever you like. — cjds
– cjds, Commented Dec 20, 2012 at 2:00
Just return something and use the function, I don't see the point of your question really... — elclanrs
– elclanrs, Commented Dec 20, 2012 at 2:03

Travis J · Accepted Answer · 2012-12-20 02:00:50Z

1

Here is one approach you could take, although the question is a little vague.

function first(){
 return a+b;
} 

function two(){
 return c+d;
}

function three(){
 var finalResult = first() + two();
}

Or, if you didn't want the value in a function, you could do this:

<script>
 var results = first() + two();
</script>

answered Dec 20, 2012 at 2:00

Travis J

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Comments

Rasmus · Accepted Answer · 2012-12-20 01:59:51Z

1

function first() {
    return a + b;
}

function two() {
    return c + d;
}

function three(result1, result2) {
    return result1 + result2;
}

Call it:

var finalResult = three(first(), two());

answered Dec 20, 2012 at 1:59

Rasmus

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Comments

cjds · Accepted Answer · 2012-12-20 02:02:04Z

1

Don't bother with the global results, i.e. result1,result2 etc. Just return the data and call 3 when ready with all

function first(){
 return a+b;
} 

function two(){
  return c+d;
}

function three(){
     return (first() + two());
 }

answered Dec 20, 2012 at 2:02

cjds

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Comments

Akhil Sekharan · Accepted Answer · 2012-12-20 02:06:09Z

1

A better way is to pass an object. It will make sure if you want to put more details, you wont have to add more arguments in the function and make it more readable.

function first(){
    return "value of one";
} 

function second(){
    return "value of two";
}


function three(data){
    var finalResult = data.first + data.second;
}

ANd call it like:

var data = {};
data.first = first();
data.second = second();

three(data);

edited Dec 20, 2012 at 2:06

answered Dec 20, 2012 at 2:00

Akhil Sekharan

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Comments

Tepken Vannkorn · Accepted Answer · 2012-12-20 02:01:50Z

0

function one( a, b ) {
   var result1 = a + b;
   return result1;
}

function two( c, d ) {
   var result2 = c + d;
   return result2;
}

function three( a, b ) {
   var finalResult = a + b;
   return finalResult;
}

To call it use three( one(), two() );

answered Dec 20, 2012 at 2:01

Tepken Vannkorn

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