Using Javascript to remove end of URL

Question

Using window.location.pathname I get "/Mobile/Evol/12-20-2011".

Using Javascript, how could I drop off everything after "Evol/" so that I get "/Mobile/Evol/"?

@MaratTanalin I second that. From what you wrote, it isn't clear what, in general, you're actually trying to accomplish. — user529758
– user529758, Commented Dec 21, 2012 at 16:56

Hunter McMillen · Accepted Answer · 2012-12-21 16:55:09Z

6

You can use a combination of the substring() and lastIndexOf() functions to easily cut off everything after the last /:

uri    = "/Mobile/Evol/12-20-2011";
newUri = uri.substring(0, uri.lastIndexOf('/'));

as @josh points out if there are more directories after "/Evol", this fails. You can fix this by searching for the string 'Evol/' then adding its length back to the substring end:

dir = "Evol/";
newUri = uri.substring(0, uri.lastIndexOf(dir) + dir.length);

Chrome console gives me this output:

> uri    = "/Mobile/Evol/12-20-2011";
"/Mobile/Evol/12-20-2011"

> dir = "Evol/";
  newUri = uri.substring(0, uri.lastIndexOf(dir) + dir.length);
"/Mobile/Evol/"

edited Dec 21, 2012 at 16:55

answered Dec 21, 2012 at 16:50

Hunter McMillen

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2 Comments

josh3736 Over a year ago

This assumes there's only one directory after Evol, which may not be correct.

Hunter McMillen Over a year ago

@josh3736 that is correct, I was only following the example that was posted. I edited to take account for your comment.

RANIL · Accepted Answer · 2012-12-21 17:04:13Z

2

Just use "split" function in JavaScript string,

var url = '/Mobile/Evol/12-20-2011';
var tokens = url.split('/');
var reqURL = token[0] + '/'+ token[1] ;

Of course the URL format must be the same some_string/some_string/some_string

answered Dec 21, 2012 at 17:04

RANIL

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Comments

user529758 · Accepted Answer · 2012-12-21 16:51:21Z

0

var str = window.location.pathname;
const sub = "Evol/";

var locEvol = str.indexOf(sub);
var endIdx = locEvol + sub.length;
var beginStr = str.substring(0, endIdx);
// beginStr contains the desired substring

answered Dec 21, 2012 at 16:51

user529758

Comments

Mike Samuel · Accepted Answer · 2012-12-21 16:51:54Z

0

Assuming you want to cut off any query and fragment completely:

url.replace(/\/Evol\/[^?#]*(?:[?#].*)?$/, '/Evol')

To break this regex down:

\/Evol\/ matches the literal text "/Evol/". The \'s are necessary since //Evol/... would be a line comment, and a / elsewhere in a regex ends the regex.
[^?#] matches anything except a query or fragment delimiter
(?:...)? just makes something optional
[?#].* matches a query or fragment start followed by any number of non-whitespace chars
$ forces the match to reach the end of the input.

answered Dec 21, 2012 at 16:51

Mike Samuel

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Comments

Alia Anis · Accepted Answer · 2020-06-13 00:47:53Z

0

One Liner:

match.url.split("/").slice(0,-1).join("/")

let array1 = "/first/second/third/fourth";
let array2="posts/stories/1234";

console.log("Result=",array1.split("/").slice(0,-1).join("/"));
console.log("Result=",array2.split("/").slice(0,-1).join("/"));

edited Jun 13, 2020 at 0:47

answered Jun 13, 2020 at 0:41

Alia Anis

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