split string method

Question

i have written a code in java as given under

public class sstring  
{  
    public static void main(String[] args)  
    {  
    String s="a=(b+c); string st='hello adeel';";  
    String[] ss=s.split("\\b");  
    for(int i=0;i<ss.length;i++)  
        System.out.println(ss[i]);  
    }  
}

and the output of this code is

a
=(
b
+
c
);
string

st
='
hello

adeel
';

what should i do in order to split =( or ); etc in two separate elements rather than single elements. in this array. i.e. my output may look as

a
=
(
b
+
c
)
;
string

st
=
'
hello

adeel
'
;

is it possible ?

Yes it is possible. See this answer: - stackoverflow.com/a/14032866/1679863 — Rohit Jain
– Rohit Jain, Commented Dec 26, 2012 at 16:38
Just noticed that the question was asked by you only. Now what didn't you understand in that solution? — Rohit Jain
– Rohit Jain, Commented Dec 26, 2012 at 16:47
actually consecutive special characters are not separated. that's why — adeel iqbal
– adeel iqbal, Commented Dec 26, 2012 at 17:17
@RohitJain thanks for your support. i think that string tokenizer class would best suit my problem. isn't it ? — adeel iqbal
– adeel iqbal, Commented Dec 26, 2012 at 17:18
@adeeliqbal.. Have you tried to modify the split method I gave to suit your situation. Just include all the delimiters you have in that character class. In this case, you have \\W. So, you can use it. StringTokenizer may work, but it is not suggested to use it. — Rohit Jain
– Rohit Jain, Commented Dec 26, 2012 at 17:20

Community · Accepted Answer · 2017-05-23 11:59:15Z

2

This matches with every find either a word \\w+ (small w) or a non-word character \\W (capital W).

It is an unaccepted answer of can split string method of java return the array with the delimiters as well of the above comment of @RohitJain.

public String[] getParts(String s) {
    List<String> parts = new ArrayList<String>();
    Pattern pattern = Pattern.compile("(\\w+|\\W)");
    Matcher m = pattern.matcher(s);
    while (m.find()) {
        parts.add(m.group());
    }
    return parts.toArray(new String[parts.size()]);
}

edited May 23, 2017 at 11:59

CommunityBot

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answered Dec 26, 2012 at 16:49

Joop Eggen

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3 Comments

Rohit Jain Over a year ago

Just to my surprise, even the asker is same. ;)

Joop Eggen Over a year ago

@RohitJain okay, today enough with SO ;S

Rohit Jain Over a year ago

@JoopEggen.. Lol ;) Good night :)

ridoy · Accepted Answer · 2012-12-26 17:29:18Z

1

Use this code there..

Pattern pattern = Pattern.compile("(\\w+|\\W)");
Matcher m = pattern.matcher("a=(b+c); string st='hello adeel';");
while (m.find()) {
System.out.println(m.group());
}

answered Dec 26, 2012 at 17:29

ridoy

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