XML Parsing (Flash AS3) from external XML (web service)

Question

My AS3 code:

loginBtn.addEventListener("mouseDown", sendData)
function sendData(e:Event) {
    var path:String = "http://server1.digitalmulia.com/~testing/webservice/auth/login";
    var myData:URLRequest = new URLRequest(path)
    myData.method = URLRequestMethod.POST
    var variables:URLVariables = new URLVariables()
    variables.username = usernameField.text
    variables.password = passwdField.text
    myData.data = variables
    var loader:URLLoader = new URLLoader()
    loader.dataFormat = URLLoaderDataFormat.VARIABLES
    loader.addEventListener(Event.COMPLETE, dataOnLoad)
    loader.load(myData)
}
function dataOnLoad(e:Event){
    var xmldata = XML(e.target.data);
    var xxx = xmldata.toString();
    var myFormat:TextFormat = new TextFormat();
    myFormat.font = "Arial";
    myFormat.size = 12;
    myFormat.bold = true;

    var myText:TextField = new TextField();
    myText.defaultTextFormat = myFormat;
    myText.selectable = true;
    myText.border = true;
    myText.text = xxx;
    myText.x = 10;
    myText.y = 200;
    myText.width = 300;
    myText.height = 100;
    addChild(myText);

}
stop()

The result:

%3C%3Fxml%20version=%221%2E0%22%3F%3E%0A%3Cxml%3E%3Cdatas%2F%3E%3Cinformation%3E%3Cpasswd%3E5f4dcc3b5aa765d61d8327deb882cf99%3C%2Fpasswd%3E%3C%2Finformation%3E%3Cerror%3E%3Citem%3EUsername%20not%20found%20or%20password%20is%20wrong%3C%2Fitem%3E%3C%2Ferror%3E%3C%2Fxml%3E%0A

What's wrong? The result which I need as similar as

<xml>
    <datas/>
    <information>
        <passwd>5f4dcc3b5aa765d61d8327deb882cf99</passwd>
    </information>
    <error>
        <item>Username is null</item>
        <item>Password is null</item>
    </error>
</xml>

I'm sorry for my bad english.

Raja Jaganathan · Accepted Answer · 2012-12-27 09:09:00Z

1

You can try with unescape(xmldata.toString()) then you will get desired output.

        function dataOnLoad(e:Event)
        {
            var xmldata:XML = XML(e.target.data);
            var xmlStr:String = unescape(xmldata.toString());
            xmldata = XML(xmlStr);          
        }

The function escape("args") converts the argument to a string and encodes it in a URL-encoded format.

escape("escape unescape");

output: escape%20unescape

The function unescape converts all hexadecimal sequences to ASCII characters. For example,

unescape("escape%20unescape");

output : escape unescape

edited Dec 27, 2012 at 9:09

answered Dec 27, 2012 at 9:01

Raja Jaganathan

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Comments

Lukasz 'Severiaan' Grela · Accepted Answer · 2012-12-28 09:09:33Z

0

I'm sure it is becuase you have chosen URLLoaderDataFormat.VARIABLES type, try other values like URLLoaderDataFormat.TEXT also when passing this to the XML constructor wrap it with try catch block as invalid data will throw errors.

answered Dec 28, 2012 at 9:09

Lukasz 'Severiaan' Grela

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