I am creating a simple c program and output of below program should be 2 but i am getting 50 dont know why (i am newbie to c) please let me know where i am missing
#include<stdio.h>
int main(int argc, char** argv) {
int a[4]={'1','2','2','\0'};
printf("The value of a is %d",a[1]);
return 0;
}
You initialised the array using ascii character codes. '2' has integer value 50.
Initialise the array as
int a[4]={1,2,2,0};
if you want it to contain integers 1,2,2,0. Or
#include<stdio.h>
int main(int argc, char** argv) {
char a[4]="121";
printf("The value of a is %c",a[1]);
return 0;
}
if you want an array of characters that can be treated as a string. (Note the use of the %c format specifier here.)
System.out.println((int) '2'); prints 50.50 is the ASCII code of '2'.
Replace '2' with 2 if you want it fixed.
When using character literals like '2' C actually thinks of them as integer types. When you print it using %d format specifier you're telling C to print the value as integer.
If you want to keep the array elements like this: '2', you'll need to change printf format to %c to get a 2 in the console.
When you wrote int a[4]={'1','2','2','\0'}; you actually initialized the array with ASCII Codes of the numbers 1 and 2.
This is because you enclosed them within single quotes thus making them characters instead of integers.
Hence the array actually takes the values int a[4]={49,50,50,0};
To rectify it, you should write the integers without the quotes:
int a[4]={1,2,2,0};
Also note that integer arrays don't need to end with '\0'. That is only for character arrays.
This line
int a[4]={'1','2','2','\0'};
tells the compiler to create an integer array of length 4 and put into it the integers from the curled braces from the right.
Characters in C are 1-byte integers, 1 is a character of 1 and it means integer value of it's ASCII code, i.e. 50. So the first element of an array gets the value of 50.
To fix you should write
int a[4]={1,2,2,0};
remember, that 0 cannot serve as an array end marker, since it is just a number.
If you suppose to get 122 output then do
char a[4]={'1','2','2','\0'};
printf("The value of a is %s",a);
since strings in C are character arrays with 0 as termination symbol.
Also you can let compiler to count values for you
char a[]={'1','2','2','\0'};
You are assigning chars not integers:
note
'2' means char use %c
2 manes int use %d
"2" means string. use %s
all are different:
in your code you can do like to print 2:
int main(int argc, char** argv) {
char a[4]={'1','2','2','\0'};
printf("The value of a is %c",a[1]);
return 0;
}
