Apply a command for each file in a folder using Windows batch script

Question

I am trying to figure out how to create a script that will take all video files in a folder videos\*.* and then use ffmpeg on each one and output the files to converted\*.mp4 where the filenames are the same.

However, I can't figure out how to get the for loop working, so that I can extract the name and extension type of file I am processing.

for %%f IN (videos\*.*) DO (convert.bat %%f)

convert.bat

ffmpeg.exe -i %1 -f mp4 converted\%~n.mp4

I have tried both with and without double quotes. However, it won't recognise the file.

Is there a typo on %~n.mp4?

MJZ
– MJZ

2012-12-27 15:08:04 +00:00
Commented Dec 27, 2012 at 15:08 — MJZ
– MJZ, Commented Dec 27, 2012 at 15:08

David Ruhmann · Accepted Answer · 2012-12-27 15:10:26Z

5

One liner batch file command:

for %%F in (videos\*.*) do ffmpeg.exe -i "%%~fF" "%%~dpF\converted\%%~nF.mp4"

Two liner as you had it: (Added call command, quotations, and ~)

for %%F IN (videos\*.*) DO (call convert.bat "%%~fF")

convert.bat (Corrected parameter usage with ~, options, and quotations)

ffmpeg.exe -i "%~f1" "%~dp1\converted\%~n1.mp4"

See for /?, call /?, ffmpeg for help.

answered Dec 27, 2012 at 15:10

David Ruhmann

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