regex, delete first part of a string

Question

I have the string 562865_numbersletterssymbols

If I want to delete, IF EXISTS; the first part (562865_), what should I search?

My guess was ^[^?:(562865_)]+$ to take what was not "562865_" (if existing ?:) until $ +$

But I discovered that (562865_) searchs every single digit and not the whole string.

How can I find the solution?

are you looking specifically for the exact sequence "562865_" or any set of numbers, followed by an underscore? — Gus
– Gus, Commented Dec 27, 2012 at 18:43
I'm not familiar with php, but why not find "562865_" in the target string, and then replace the match(if any) with an empty string? I would prefer this approach to finding what's "not" 562865_ — Vinod Vishwanath
– Vinod Vishwanath, Commented Dec 27, 2012 at 18:46
$your_var = str_replace('562865_', '', $your_var), no? Sorry for not posting this as an answer, but I can't believe in this question being extremely localized. — raina77ow
– raina77ow, Commented Dec 27, 2012 at 18:46

Get Off My Lawn · Accepted Answer · 2012-12-27 18:53:22Z

1

The easiest way that I was able to come up with is this. It will work not only for that name but any others with the same format.

<?php
$string = "562865_numbersletterssymbols";

echo preg_replace("/^\d+_/", "", $string);

answered Dec 27, 2012 at 18:53

Get Off My Lawn

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Comments

mtrbean · Accepted Answer · 2012-12-27 18:50:06Z

0

If you want to stick with regex, try ^[\d]+_(.+)$

the _ splits the string into 2 parts, and you need the second part in parenthesis (.+)

answered Dec 27, 2012 at 18:50

mtrbean

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[\d] - why you put a character class into a character class?

I'd have problems if I don't find that exact initial part, because it will strip away a lot more of the string, till the first "_"

@user1722791 if your initial part is always 562865_, how about ^562865_(.+)$ ?

Mewster · Accepted Answer · 2012-12-27 19:30:24Z

0

Thanks to raina77ow, the easiest way is always the best choice.

$your_var = str_replace('562865_', '', $your_var)

answered Dec 27, 2012 at 19:30

Mewster

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