so i'm looking for a way to simulate an 404 error, i tried this :
throw $this->createNotFoundException();
and this
return new Response("",404);
but none does work.
Add a comment
|
1 Answer
You can find the solution in the Symfony2 documentation:
http://symfony.com/doc/2.0/book/controller.html
Managing Errors and 404 Pages
public function indexAction()
{
// retrieve the object from database
$product = ...;
if (!$product) {
throw $this->createNotFoundException('The product does not exist');
}
return $this->render(...);
}
There is a short information in the documentation:
"The createNotFoundException() method creates a special NotFoundHttpException object, which ultimately triggers a 404 HTTP response inside Symfony."
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException
In my scripts i've made it like this:
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException
/**
* @Route("/{urlSlug}", name="test_member")
* @Template()
*/
public function showAction($urlSlug) {
$test = $this->getDoctrine()->.....
if(!$test) {
throw new NotFoundHttpException('Sorry not existing!');
}
return array(
'test' => $test
);
}
2 Comments
ferdynator
+1 because you
throw and not return the exception. Saved me some trouble.ferdynator
NO! It will not work with
return, because that is not a valid Response Object. throw it and live happily after.