1

in a bash script, I have :

mkv="xxxx E05 xxxx"

if [[ $mkv =~ E[0-9]{2} ]] ; then echo FOUND; fi

good. this tells me if $mkv matches against E[0-9]{2}, but this is not what I want.

I want to get the matching string (i.e. 05 in my example)

I put a reference () in my regexp, hoping I'd be able to get it later, but I could not.

I tried :

if [[ $mkv =~ E([0-9]{2}) ]] ; then echo FOUND $1; fi

if [[ $mkv =~ E([0-9]{2}) ]] ; then echo FOUND \1; fi

etc... but all of them failed

thanks !

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1 Answer 1

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2

You can use the BASH_REMATCH array to get the parts that matched:

if [[ $mkv =~ E([0-9]{2}) ]] ; then echo FOUND ${BASH_REMATCH[1]} ; fi

${BASH_REMATCH[0]} will contain the whole/full match (Exx), ${BASH_REMATCH[1]} the first captured group (only the digits here).

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1 Comment

Just to add, Here REMATCH is not re-match rather regular expression match.

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