Android/php Jsonobject error parsing

Question

i have a problem with jsonObject.

in android app i have:

try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
        Log.e("JSON Parser2", "json: "+json);
    }

the logcat is:

01-03 16:50:09.239: E/JSON Parser(17447): Error parsing data org.json.JSONException: Value [] of type org.json.JSONArray cannot be converted to JSONObject 
01-03 16:50:09.239: E/JSON Parser2(17447): json: [][][]{"code":0,"message":"Segnalazione inviata correttamente"}

in php i have:

$response = array();
$response["code"] = $e['code'];
$response["message"] = $e['message'];
echo json_encode($response);

thanks

[][][] are spurious in the json you receive.

Boris Strandjev
– Boris Strandjev

2013-01-03 15:58:43 +00:00
Commented Jan 3, 2013 at 15:58 — Boris Strandjev
– Boris Strandjev, Commented Jan 3, 2013 at 15:58

ρяσѕρєя K · Accepted Answer · 2013-01-03 16:31:50Z

1

Change your PHP JsonObejct Creation Code as :

echo json_encode($response, JSON_FORCE_OBJECT);

and now you can parse current json string as :

  String str_final_json=json.replace("{}{}{}","");   

 // convert string to jsonObject
 JSONObject jObj = new JSONObject(str_final_json);

// get code from json object
String str_code=jObj.getString("code");

// get message from json object
String str_message=jObj.getString("message");

edited Jan 3, 2013 at 16:31

answered Jan 3, 2013 at 16:07

ρяσѕρєя K

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8 Comments

Atomico Over a year ago

i suppose you mean String str_code=jObj.getString("code");

Atomico Over a year ago

but it don't work 01-03 17:16:29.039: W/System.err(20954): org.json.JSONException: No value for code (same for message)

ρяσѕρєя K Over a year ago

@Atomico : you have added echo json_encode($response, JSON_FORCE_OBJECT); in php file ?

ρяσѕρєя K Over a year ago

@Atomico : now what json string you are getting from server?plz share with me

Atomico Over a year ago

just for your curiosity.. i found the problem :) in the code i wrong put echo json_encode($response, JSON_FORCE_OBJECT); more than 1 time.. my fault :)

|

Mike Marshall · Accepted Answer · 2013-01-03 16:00:58Z

0

Use JSONArray if your top level object is an array.

   try {
        jArr = new JSONArray(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
        Log.e("JSON Parser2", "json: "+json);
    }

answered Jan 3, 2013 at 16:00

Mike Marshall

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Comments

Lalith B · Accepted Answer · 2013-01-03 16:23:39Z

0

Guess the issue is with your php code try to change your php code like below

$response = array("code" => $e['code'], "message" =>$e['message']);
echo json_encode($response);

answered Jan 3, 2013 at 16:23

Lalith B

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2 Comments

Atomico Over a year ago

01-03 17:32:29.279: E/JSON(21931): json: {}{}{}{"code":null,"message":null}

Lalith B Over a year ago

Try var_dump($e) and check if you get proper results.

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