Echoing PHP within HTML

Question

I am currently trying to create a shopping cart for my website and I have images of products stored in a database and I want to include them within <img src> . By putting $get_row[imagesrc] within the src. I need to know the correct way to add it to the below code as I dont fully understand the ' and . tags

    echo '<p>'.$get_row['name'].'<br/>'.$get_row['description'].'<br/>'.$get_row['imagesrc'].
'<br/>&pound;'.number_format($get_row['price'],2).'<a href="cart.php?add='.$get_row['id'].'">Add</a></p>';

You will really get mad in generating html this way - get into some templating engine like Smarty or Twig. — moonwave99
– moonwave99, Commented Jan 7, 2013 at 17:15

BenM · Accepted Answer · 2013-01-07 17:15:10Z

4

This should achieve what you're looking for:

echo '<p>'.$get_row['name'].'<br/>'.$get_row['description'].'<br/><img src="'.$get_row['imagesrc'].'" /><br/>&pound;'.number_format($get_row['price'],2).'<a href="cart.php?add='.$get_row['id'].'">Add</a></p>';

The ' character defines a string literal when it is wrapped around a series of characters.
The . character is used for concatenating strings for output or storage.

answered Jan 7, 2013 at 17:15

BenM

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abhshkdz · Accepted Answer · 2013-01-07 17:15:43Z

2

echo '<p>'.$get_row['name'].'<br/>'.$get_row['description'].'<br/><img src="'.$get_row['imagesrc'].'"><br/>&pound;'.number_format($get_row['price'],2).'<a href="cart.php?add='.$get_row['id'].'">Add</a></p>';

answered Jan 7, 2013 at 17:15

abhshkdz

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Toddish · Accepted Answer · 2013-01-07 17:19:02Z

2

. concatenates two strings, and ' is wrapped around a string.

so

echo 'Hello '.'World'; // Shows Hello World

I'd split yours up to make it easier to read:

echo '<p>';
    echo $get_row['name'].'<br/>';
    echo $get_row['description'].'<br/>';
    echo '<img src="'.$get_row['imagesrc'].'" /><br/>';
    echo '&pound;'.number_format($get_row['price'],2);
    echo '<a href="cart.php?add='.$get_row['id'].'">Add</a>';
echo '</p>';

But it all looks OK.

answered Jan 7, 2013 at 17:19

Toddish

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Pedro del Sol · Accepted Answer · 2013-01-07 17:14:42Z

1

echo '<p>'.$get_row['name'].'<br/>
<img src="'.$get_row['imagesrc'].'" alt="'.$get_row['name'].'"><br/>
<br/>&pound;'.number_format($get_row['price'],2).'
<a href="cart.php?add='.$get_row['id'].'">Add</a></p>';`

answered Jan 7, 2013 at 17:14

Pedro del Sol

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Comments

BenM · Accepted Answer · 2013-01-07 17:15:34Z

1

echo '<img src="'.$get_row['imagesrc'].'">';

Try that.

edited Jan 7, 2013 at 17:15

BenM

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answered Jan 7, 2013 at 17:15

SeanWM

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Community · Accepted Answer · 2017-05-23 12:14:23Z

1

A specific answer has been given:

echo '<img src="'.$get_row['imagesrc'].'">';

Nonetheless, it's worth adding that you should:

You should escape output - with htmlspecialchars() or otherwise.

echo '<img src="' . htmlspecialchars($get_row['imagesrc']) . '">';

Read the documentation on PHP Strings.

edited May 23, 2017 at 12:14

CommunityBot

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answered Jan 7, 2013 at 17:16

Jason McCreary

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phpisuber01 · Accepted Answer · 2013-01-07 17:18:43Z

1

Check out this way of including PHP in your HTML. It's much easier to read and maintain. The last line in the paragraph is your image tag.

<p>
    <?php echo $get_row['name']; ?><br/>
    <?php echo $get_row['description']; ?><br/>
    <?php echo $get_row['imagesrc']; ?><br/>
    &pound;<?php echo number_format($get_row['price'],2); ?>
    <a href="cart.php?add=<?php echo $get_row['id']; ?>">Add</a>
    <img src="<?php echo $get_row['imagesrc']; ?>" />
</p>

answered Jan 7, 2013 at 17:18

phpisuber01

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