Regex to bulk replace attributes[x] with getAttribute in HTML files

Question

In a boatload of HTML pages, I need to replace all strings like this:

language[0].attributes[24].value;

with this:

language[0].getAttribute("attr"+24);

where '24' can be any number.

I thought I could use Notepad++'s Find and Replace with regular expressions to do this, but have had no luck so far after much trial and error. I don't want to have to do this manually.

(This is because, when I upgraded to IE10, all the text on the webpages I support went out of whack. It seems that by definition XML attributes can be in any order, and that newer versions of IE reorder them. I now need to reference the attributes by name instead of index.)

Appreciate the help.

FrankieTheKneeMan · Accepted Answer · 2013-01-07 21:33:51Z

3

find the following regular expression:

\.attributes\[(\d+)\]\.value

And replace it with

.getAttribute("attr"+\1)

http://regexr.com?33b0j <-- See it in action!

answered Jan 7, 2013 at 21:33

FrankieTheKneeMan

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Hosein · Accepted Answer · 2013-01-07 21:34:56Z

0

You should use some wildcard replace tools in some text editor. I personally use VS. MS-Office programs such as word has that possibility too.

answered Jan 7, 2013 at 21:34

Hosein

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Andreas · Accepted Answer · 2013-01-07 21:35:32Z

0

Find what: \.attribute\[(\d+)\]\.value;
Replace with: .getAttribute\("attr" + \1\);

(I had to escape the brackets in the replace value for my version of Notepad++ to)

answered Jan 7, 2013 at 21:35

Andreas

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3 Comments

FrankieTheKneeMan Over a year ago

You don't have to escape the brackets because of Notepad++, it's because brackets delineate character sets in Regular Expressions.

Andreas Over a year ago

I'm talking about the replace value not the find value

FrankieTheKneeMan Over a year ago

Okay. Got confused because you don't have any brackets in your replace value, and thought you mistyped.

bukart · Accepted Answer · 2013-01-07 21:38:11Z

0

Tested with notepad++

language\[0\].attributes\[\s*(\d+)\s*\].value;

replaced with

language[0].getAttribute\("attr"+\1\);

answered Jan 7, 2013 at 21:38

bukart

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