Find values in char array c++

Question

I have a char array and the text actually looks like XML:

<root>
<number>1</number>
<counter>2</counter>
<lastNumber>3</lastNumber>
</root>

I need to get these values and store them to variables so I can work with them.

Any idea how to do that?

Thank you

That doesn't look like a char array at all, it looks a lot like XML... — K-ballo
– K-ballo, Commented Jan 9, 2013 at 22:05

barryjones · Accepted Answer · 2013-01-09 22:06:01Z

6

You could use TinyXML, to parse the file. http://www.grinninglizard.com/tinyxml/ Its a open source library to parse XML files in C++.

answered Jan 9, 2013 at 22:06

barryjones

2,3791 gold badge18 silver badges21 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Community · Accepted Answer · 2017-05-23 11:52:50Z

2

You should formulate a better question, but the general idea is clear and so I suggest to use a library such as boost::spirit or, if you can arrange your data in a different way, you can use boost::config which is probably a much simpler approach and here is an example .

edited May 23, 2017 at 11:52

CommunityBot

11 silver badge

answered Jan 9, 2013 at 22:09

user1824407

4,6394 gold badges18 silver badges21 bronze badges

2 Comments

hate-engine Over a year ago

boost::spirit for writing yet another xml parser? No way, unless you are doing homework. There are bunch of production-ready xml parsers to use, so leave boost::spirit for really new languages.

user1824407 Over a year ago

@hate-engine all you can say right now it's that the OP needs to parse a file, no reference about any XML specific schema or DTD of any kind, in this case, generic case, boost::spirit is the only way to go, also there are many case where the word XML it's not enough, there are many schemas for XML.

Collectives™ on Stack Overflow

Find values in char array c++

2 Answers 2

Comments

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related