saving return code and returning it in bash

Question

I'd like to do this in bash

#!/bin/bash

func(){
    return 1;
}

e=func
echo some text
exit e

but I'm getting

exit: func: numeric argument required

AFAIK variables in bash are without a type, how to "convert" it to int to satisfy requirement?

fge · Accepted Answer · 2013-01-10 21:00:07Z

19

You need to add a $ in front of a variable to "dereference" it. Also, you must do this:

func
e=$?
# some commands
exit $e

$? contains the return code of the last executed "command"

Doing e=func sets string func to variable e.

answered Jan 10, 2013 at 21:00

fge

122k35 gold badges266 silver badges340 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Thanks, sequence of func and e=$? did the trick, missing $ was just a typo.