py2exe - executable does not start

Question

I've compiled my app with this script in order to avoid compiling error on libmzq and MSVCP90 dlls:

from distutils.core import setup
import py2exe

setup(console=[{"script": "Int_assortimenti.py"}],
       options = {
        "py2exe": {
            "dll_excludes": ["libzmq.dll", "MSVCP90.dll"]
        }
    })

I obtain my executable but when I run it the result is:

enter image description here

How can I solve this problem? Consider that n my application matplotlib is not used.

Thanks a lot in advance: form me is crucial to solve this problem!

M

Bruno Gelb · Accepted Answer · 2013-01-15 00:28:02Z

1

Please, look here ("Data files" section): http://www.py2exe.org/index.cgi/MatPlotLib

This might help you with that issue.

Edit. Oh, I'm sorry I had read your question inattentive :( If your app doesn't use matplotlib, I think you can just add it to excludes. Smth like this:

excludes = ['matplotlib'] # add here all libraries (separated by commas) that you don't need in app

setup(console=[{"script": "Int_assortimenti.py"}],
   options = {
    "py2exe": {
        "excludes": excludes,
        "dll_excludes": ["libzmq.dll", "MSVCP90.dll"]
    }
})

edited Jan 15, 2013 at 0:28

answered Jan 14, 2013 at 3:00

Bruno Gelb

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1 Comment

Manuel Zompetta Over a year ago

Thanks, already done and resolved. But I have a problem: if I have to include in the data_file another file for the app (an image in this case) the setup file: from distutils.core import setup import py2exe import matplotlib file_dati=[] file_dati.append(matplotlib.get_py2exe_datafiles()) file_dati.append(('img1','C:\Users\MZompetta.000\Desktop\20130114_assortimenti\img1.gif')) setup(console=[{"script": "Int_assortimenti.py"}], options = { "py2exe": { "dll_excludes": ["libzmq.dll", "MSVCP90.dll"] } }, data_files=file_dati ) do not function properly

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