How would I set PHP to randomly chose between these two sets of variables to use:
$key = goop;
$john = heck yeah;
and this
$key = roop;
$john = reck reah;
Thanks ever so much! :)
3 Answers
For example:
if ( rand(0,1) )
{
$key = "goop";
$john = "heck yeah";
}
else
{
$key = "roop";
$john = "reck reah";
}
15 Comments
Philip Whitehouse
By far the simplest solution,
rand() is an int, so it should be even chanceI'd use mt_rand() as it is faster and should be more random.
Martin
Mine will maintain the pairs ;)
|
I'd recommend using an array:
$selection = array(
array('goop', 'heck yeah'),
array('roop', 'reck reah')
);
shuffle($selection);
list($key, $john) = array_pop($selection);
5 Comments
Martin
Simply add another array into
$selection. It'll support as many as you want to add inMartin
@SolèneLeVan
list is a function -- it assigns the array values to the variables $key and $johnStore the values in an array, and then use rand() to generate the values:
$key_vals = array('goop', 'roop', 'toop');
$john_vals = array('heck yeah', 'reck reah', 'leck leah');
$key = $key_vals[rand(0, (count($key_vals) - 1))];
$john = $john_vals[rand(0, (count($john_vals) - 1))];
You can easily extend this by adding values to the respective arrays, and increasing the maximum random number (i.e. second argument in rand()).
11 Comments
BenM
No problem - there's more than one way to skin a cat :)
BenM
See my updated answer on how to extend this to include more values.
BenM
If the pairs always have to match (i.e.
goop with heck yeah) it'd be better to use Martin's answer. |