display random image url from folder

Question

I have a php code which uses every image in a folder and echos the url on my page.

what i need help with is making the php code randomize the list of urls each time the page is loaded.

The code that i have is:

<?php 
 if ($handle = opendir('images')) {
   while (false !== ($file = readdir($handle)))
      {
          if ($file != "." && $file != "..")
      {
            $thelist .= '<div data-delay="5"><img src="images/'.$file.'"></div>';
          }
       }
  closedir($handle);
  }
?>
<?=$thelist?>

many thanks

So, what is the problem and what do you want?

samayo
– samayo

2013-01-12 23:20:33 +00:00
Commented Jan 12, 2013 at 23:20 — samayo
– samayo, Commented Jan 12, 2013 at 23:20

Till Helge · Accepted Answer · 2013-01-12 23:23:56Z

2

Easiest solution would be to put all filenames into an array and then use shuffle() to mix it up. Then you can iterate over the array and output the images. It should look something like this:

<?php 
 $thelist = "";
 if ($handle = opendir('images')) {
   $images = array();
   while (false !== ($file = readdir($handle))) {
      if ($file != "." && $file != "..") {
            array_push($images, 'images/'.$file);
      }
   }
   closedir($handle);
   shuffle($images);
   foreach ($images as $image) {
      $thelist .= '<div data-delay="5"><img src="'.$image.'"></div>';
   }
   echo $thelist;
 }
?>

By using glob() instead of opendir() you could shorten the code significantly, as glob() returns an array and then you only would need to shuffle that one.

answered Jan 12, 2013 at 23:23

Till Helge

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Comments

Libert KHE · Accepted Answer · 2013-01-12 23:24:36Z

0

put your file links into an array and shuffle it with the function shuffle()

<?php 

if ($handle = opendir('images')) {
    $fileTab = array();
    while (false !== ($file = readdir($handle))) {
        if ($file != "." && $file != "..") {
            $fileTab[] = $file; 
        }
    }
    closedir($handle);
    shuffle($fileTab);
    foreach($fileTab as $file) {
        $thelist .= '<div data-delay="5"><img src="images/'.$file.'"></div>';
    }
}
?>
<?=$thelist?>

answered Jan 12, 2013 at 23:24

Libert KHE

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Comments

Roy · Accepted Answer · 2013-01-12 23:24:44Z

0

Instead of directly creating divs in the while loop, use it only to store all urls in an Array. Then shuffel that array, and use a foreach loop in order to populate $thelist.

answered Jan 12, 2013 at 23:24

Roy

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Comments

Austin Brunkhorst · Accepted Answer · 2013-01-12 23:56:44Z

0

Why don't you use glob()?

$images = glob('images/*.{jpg,png,gif}', GLOB_BRACE);

shuffle($images);

foreach($images as $image) {
    echo '<div data-delay="5">
              <img src="', $image ,'">
          </div>';
}

edited Jan 12, 2013 at 23:56

answered Jan 12, 2013 at 23:29

Austin Brunkhorst

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